Understanding Current in Series Circuits: Explaining 6A with 12V and 2 Ohms

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The discussion centers on calculating current in a series circuit, specifically addressing a scenario where 12V and 2 Ohms yield a current of 6A. Participants debate whether the current should be calculated using only the resistance of the given resistor or the total resistance in the circuit. Concerns are raised about the example's accuracy, highlighting that real-world factors, such as the changing resistance of a light bulb as it heats, complicate the scenario. The importance of clarifying these real-world implications for students is emphasized, as incorrect assumptions can lead to confusion. Overall, the conversation underscores the distinction between ideal circuit theory and practical applications.
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Take this question as an example
ImageUploadedByPhysics Forums1440066974.082733.jpg

They asked for the current flowing through the bulb and the answer is 6A
I know that it's 12V divided by 2 ohms(2 ohm is the resistance of resistor X) , but why? I thought the current is supposed to be 12V divided by the resistance of bulb and resistor X(total resistance of resistors) since its arranged in series?
 
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As stated, the voltage across the resistor X is measured at 12 V, so the other parts of the circuit shouldn't matter.
 
Yes, current would be 12/(rtotal), where rtotal is the sum of the series resistances.

I'm not able to agree or disagree with you on the correctness of the textbook's answer, because you haven't disclosed the exact wording of the question. The figure you selected to use as an example is not a particularly good choice---because it examplifies a fundamental wiring "mistake".
 
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olivermsun said:
As stated, the voltage across the resistor X is measured at 12 V, so the other parts of the circuit shouldn't matter.

for a idea circuit, yes you could say that. But if it was a real world circuit, that is no longer true. The light globe will have significant resistance
which will change as it heats up

NascentOxygen said:
The figure you selected to use as an example is not a particularly good choice---because it examplifies a fundamental wiring "mistake".

indeed

@Lim Y K, can you recognise the problem ?Dave
 
davenn said:
for a idea circuit, yes you could say that. But if it was a real world circuit, that is no longer true. The light globe will have significant resistance
which will change as it heats up
I realize that is the case for a real incandescent lightbulb, but since the heated filament resistance, wasn't given in the problem, I'm assuming that the student isn't expected to incorporate that information in the solution.
 
maybe but they need to be informed that it isn't like that in the real world and you didn't give that clarification :smile:

the poor guy is already getting confused enough with incorrectly drawn circuits ...
 
olivermsun said:
As stated, the voltage across the resistor X is measured at 12 V, so the other parts of the circuit shouldn't matter.
This is not the case in the figure I'm seeing.
 
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