Understanding Einstein Notation

schwarzschild
Messages
14
Reaction score
1
I thought that when you used a roman letter such as v that you started at 1 instead of 0. For instance if you had:
A^v C_{\mu v}

Wouldn't that just be: A^1C_{\mu 1} + A^2C_{\mu 2} + A^3C_{\mu 3} ?

(this is one of the problems with a solution from Schutz's book and the solution starts with v = 0 )
 
Physics news on Phys.org
Are you sure its not a \nu instead of a v?
 
I think in many notations the index normally represents a 4-vector(though it doesn't HAVE to be 4 dimensions), which in some(most?) notations start with 0. Any pairs of indices just implies a sum. I think for everything I've ever done the first index is 0 rather than 1.
 
Wow! Thanks for pointing that out - the two are confusingly similar in appearance :biggrin:.
 
schwarzschild said:
Wow! Thanks for pointing that out - the two are confusingly similar in appearance :biggrin:.

Usually Latin indicies start i,j,k ... if the author has indicated a different convention between Latin and Greek indecies.
 
A lot of older books use the convention that Latin versus Greek indices indicates spacelike indices versus ones that range over all four dimensions. The convention you'll see more commonly in newer books is to use abstract index notation http://en.wikipedia.org/wiki/Abstract_index_notation , with Latin indices indicating that they're abstract indices, Greek meaning that they refer to a particular basis.
 
  • Like
Likes cianfa72
In Philippe G. Ciarlet's book 'An introduction to differential geometry', He gives the integrability conditions of the differential equations like this: $$ \partial_{i} F_{lj}=L^p_{ij} F_{lp},\,\,\,F_{ij}(x_0)=F^0_{ij}. $$ The integrability conditions for the existence of a global solution ##F_{lj}## is: $$ R^i_{jkl}\equiv\partial_k L^i_{jl}-\partial_l L^i_{jk}+L^h_{jl} L^i_{hk}-L^h_{jk} L^i_{hl}=0 $$ Then from the equation: $$\nabla_b e_a= \Gamma^c_{ab} e_c$$ Using cartesian basis ## e_I...
Thread 'Can this experiment break Lorentz symmetry?'
1. The Big Idea: According to Einstein’s relativity, all motion is relative. You can’t tell if you’re moving at a constant velocity without looking outside. But what if there is a universal “rest frame” (like the old idea of the “ether”)? This experiment tries to find out by looking for tiny, directional differences in how objects move inside a sealed box. 2. How It Works: The Two-Stage Process Imagine a perfectly isolated spacecraft (our lab) moving through space at some unknown speed V...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. The Relativator was sold by (as printed) Atomic Laboratories, Inc. 3086 Claremont Ave, Berkeley 5, California , which seems to be a division of Cenco Instruments (Central Scientific Company)... Source: https://www.physicsforums.com/insights/relativator-circular-slide-rule-simulated-with-desmos/ by @robphy
Back
Top