Understanding existence theorem of (strong) solution of SDE

  • Context: Graduate 
  • Thread starter Thread starter Paalfaal
  • Start date Start date
  • Tags Tags
    Existence Theorem
Click For Summary
SUMMARY

The discussion centers on the existence theorem of strong solutions for stochastic differential equations (SDEs), specifically the equation defined as X_t = X_0 + ∫_0^t b(s,X_s)ds + ∫_0^t σ(s,X_s)dB_s. Key assumptions include the joint measurability and adaptation of b and σ to the filtration {ℱ_t}_{t≥0}, along with Lipschitz and linear growth conditions. The iterative scheme for approximating solutions is presented, but confusion arises regarding the martingale property of X_t^n, particularly in relation to the Lebesgue integral. The conversation highlights the necessity of clarifying whether X_t is a martingale, especially when the drift term b(t,x) is non-zero.

PREREQUISITES
  • Understanding of stochastic differential equations (SDEs)
  • Familiarity with Itô integrals and their properties
  • Knowledge of martingale theory and Doob's martingale inequality
  • Basic concepts of filtration in probability theory
NEXT STEPS
  • Study the properties of Itô integrals in detail
  • Research the implications of Doob's martingale inequality on SDEs
  • Examine the conditions under which a process is classified as a martingale
  • Explore the role of drift terms in stochastic processes and their impact on martingale properties
USEFUL FOR

Mathematicians, statisticians, and financial analysts working with stochastic processes, particularly those involved in the theoretical aspects of stochastic differential equations and martingale theory.

Paalfaal
Messages
13
Reaction score
0
I'm currently working my way through the existence theorem of strong solutions for the stochastic differential equation
## X_t = X_0 + \int_0^t b(s,X_s)ds + \int_0^t \sigma(s,X_s)Bs ##,
Where ## \int_0^t \sigma(s,X_s)Bs ## is the Ito integral. The assumptions are:
1: ## b,\sigma ## are jointly measurable and adapted to the filtration ## \{ \mathcal{F}_t\}_{t\geq0} ## .
2: ## b,\sigma ## satisfy the Lipschitz- and linear growth bound conditions.
3: ## \left| | X_0 | \right|_{L^2(\Omega)} < \infty ## and ## X_0 ## is ## \mathcal{F}_0##-measurable.
The iterative scheme
##
\begin{align}
\begin{cases}
X_t^0 &= X_0, \\
X_t^{n+1} &= X_0 + \int_0^t b(s,X_s^{n})ds + \int_0^t \sigma(s,X_s^{n}) dB_s,
\end{cases}
\end{align}
##
is introduced. A bit into the proof we need to use Doobs martingale inequality on ##X_t^{n+1} - X_t^n ##. My problem is that I fail to see how the previous expression is a martingale (wrt the filtration ## \{ \mathcal{F}_t\}_{t\geq0} ##). I know it suffices to show that ## X_t^n ## is a martingale. It is true that the Ito integral is a martingale, but what happens with the Lebesgue (or Riemann) integral? I have read the proof in several textbooks (Øksendal, Klöden-Platen, Kuo), none of the argued explicitly why ## X_t^n ## is a martingale, but all og them use Doobs martingale inequality.

By the assumptions it seems clear that ## X_0 ## is a martingale, but the Lebesgue integral seems to get in the way of proving it for general ## n ##.
 
Last edited:
Physics news on Phys.org
Sorry, I was wrong in two spots; Klöden-Platen does not use Doobs martingale inequality, but rather the 'Markov inequality':
## P(|X| > a) \leq \frac{1}{a^r}E[|X|^r] ##
for ##a,r > 0 ##. And thus I don't need to show that ##X_t^n## is a martingale. Moreover, Kuo uses 'Doobs submartingale inequality'. Still, I don't understand how ## X_t^n ## can be a martingale..
 
Last edited:
I would appreciate it if someone could clear up the martingale problem: The SDE

## X_t = X_0 + \int_0^t b(s,X_s)ds + \int_0^t \sigma(s,X_s)dB_s ##

as I understand it, is NOT a martingale wrt ## \{ \mathcal{F}_t:t\in [0,T] \} ## unless the drift term ## b(t,x) ## is zero. In Theorem 10.2.2 in the textbook "Klöden-Platen:Numerical solution to stochastic differential equations(1990)" the Doob inequality is used in eqns (10.2.14),(10,2,15). The Doob inequality reads

## E\big[ \sup\limits_{0\leq s\leq T} |X_s|^p \big] \leq \Big(\frac{p}{p-1}\Big)^p E\big[ |X_t|^p \big]. ##

But this inequality is only true for martingales, and ## X_t ## is not a martingale wrt ## \{ \mathcal{F}_t:t\in [0,T] \} ##. There are two possibilities:

1. The book is wrong (which I highly doubt)
2. I am wrong, and ## X_t ## is a martingale.

Please help!
 

Similar threads

  • · Replies 0 ·
Replies
0
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
4
Views
2K