Understanding Fluid Resistance & Velocity

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Fluid resistance is influenced by velocity, and its dependence can be either linear (v) or quadratic (v^2). To determine the nature of this relationship, one can conduct experiments, such as using a submerged block of wood in water with a spring or rubber band to measure the force required to move the block at various velocities. The general form of fluid resistance can be expressed as a power series: F(v) = a v + b v^2 + c v^4, where the linear term (a v) is often the most significant contributor. In turbulent flow, the quadratic term (v^2) relates to the kinetic energy of the fluid, linking energy to force and displacement.
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fluid resistance

how to know the fluid resistance is depend on v or v^2 ??
 
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Are you asking why fluid resistance is velocity dependent? Or are you asking how to determine whether the dependence goes linear or whether it goes quadratic with velocity?
 


Originally posted by Newton1
how to know the fluid resistance is depend on v or v^2 ??

Well, you could look it up. Or you could run some experiments. A simple experiment might use a tub or water and a submerged block of wood, with a spring or rubber band providing a measurable force to move the block, and a stopwatch.

Experiments in the tub are always fun.
 
I'm going to guess it depends on v^1... let us know when you find out. :smile:
 
It is almost certainly a power series expansion in powers of velocity, with the linear term being the most important contributor. In other words:

F(v) = a v + bv^2 + cv^4 + ...

It would be a fun experiment to determine a, b, c,...
 
The v^2 in the formula for turbulent current is an energy thing: the kinetic energy of the fluid whirls goes with v^2, and energy equals force times deplacement.
 
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...

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