Understanding Forces on a Frictionless Inclined Plane - Explained

[student85]

We have a block on a frictionless inclined plain. Someone's hand is pushing the block up with constant velocity. So, the forces acting on the block are the normal force, gravitational force...and is that it? I mean the block is moving at constant speed upward so why should that be a force. I think I am wrong here...but why?

 

[xAxis]

We have a block on a frictionless inclined plain. Someone's hand is pushing the block up with constant velocity. So, the forces acting on the block are the normal force, gravitational force...and is that it?

Yes that's it

 

[quasar987]

The block is moving at constant speed. That means no acceleration. No acceleration ==> no force. But as you said, there is gravity and a normal force acting on the block. So it must be that the hand pushing the block exerts a force such that it counter-balances the other 2 and makes the net force 0.

 

[mathlete]

The block is moving at constant speed. That means no acceleration. No acceleration ==> no force.

no *net* force, of course, like you say at the end :)

 

[xAxis]

Yes that's it

Sorry, my mistake. Of course Quasar is right