Understanding Gauss's Law: When to Apply and When it Fails

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SUMMARY

This discussion clarifies the application and limitations of Gauss's Law in electrostatics. Specifically, it highlights that Gauss's Law can be misleading when applied to systems with discontinuous charge distributions, such as dipoles. The integral form of Gauss's Law, represented as ∮ E·dS = 0, indicates that while the net electric flux through a closed surface may be zero, the electric field is not necessarily zero at every point on that surface. Understanding this distinction is crucial for correctly applying Gauss's Law in various scenarios.

PREREQUISITES
  • Understanding of electric fields and flux
  • Familiarity with Gauss's Law and its mathematical formulation
  • Knowledge of point charges and dipole configurations
  • Basic principles of electrostatics
NEXT STEPS
  • Study the mathematical derivation of Gauss's Law
  • Explore applications of Gauss's Law in symmetrical charge distributions
  • Investigate the behavior of electric fields around dipoles
  • Learn about the limitations of Gauss's Law in complex charge configurations
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Students of physics, educators teaching electrostatics, and professionals in fields requiring a solid understanding of electric fields and Gauss's Law.

dipole
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This is not a homework question.

I'm just having trouble understanding when it's appropriate to apply Gauss's law or not, and under what conditions does it fail.

For example, suppose I have two point charges forming a dipole. If I draw a cylinder around them, then the total charge enclosed is zero, implying that the field is zero.

However, this is obviously not true for a dipole.

So would I be using Gauss's law incorrectly in this case, or does it not applying to discontinuous charge distributions, or what?
 
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dipole said:
This is not a homework question.

I'm just having trouble understanding when it's appropriate to apply Gauss's law or not, and under what conditions does it fail.

For example, suppose I have two point charges forming a dipole. If I draw a cylinder around them, then the total charge enclosed is zero, implying that the field is zero.

No, it implies that the closed surface integral of a certain projection of the electric field is zero. Not that the field is zero at each point on the enclosing surface.
 
dipole said:
For example, suppose I have two point charges forming a dipole. If I draw a cylinder around them, then the total charge enclosed is zero, implying that the field is zero.
Gauss's Law would say ##\oint \vec{E}\cdot d\vec{S} = 0##. This means the electric flux into a volume is balanced by the electric flux out of the volume. It doesn't mean ##\vec{E}=0##, which would mean there is no electric flux at all into or out of the volume.
 

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