Understanding how to re-draw circuits

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SUMMARY

This discussion focuses on understanding how to analyze and redraw electrical circuits, specifically using Kirchhoff's Current Law (KCL) and series-parallel resistor combinations. The user seeks clarification on identifying series and parallel components and simplifying the circuit to find unknown voltages and currents. Key values provided include I1=4A, I2=1.33A, I3=0.67A, I4=2.67A, and Va=8.0V. The recommended approach involves simplifying the circuit step-by-step, particularly combining resistors R5 and R3, and applying KCL at nodes Va and Vb.

PREREQUISITES
  • Understanding of Kirchhoff's Current Law (KCL)
  • Familiarity with series and parallel resistor combinations
  • Basic knowledge of circuit analysis techniques
  • Ability to interpret circuit diagrams
NEXT STEPS
  • Learn how to apply Kirchhoff's Current Law (KCL) in circuit analysis
  • Study techniques for simplifying complex circuits
  • Explore series and parallel resistor calculations in detail
  • Investigate the impact of removing circuit components on current and voltage
USEFUL FOR

Electrical engineering students, circuit designers, and anyone looking to improve their skills in circuit analysis and simplification techniques.

Lopez
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Homework Statement



I need to find I1,I2,I3,Va,Vb but i don't even know to read the circuit. i know how to to do series circuits and parallel circuits but not this. How do i read this circuit and know which ones are in parallel or in series. is there a way to re-draw it? I have the solution and answer. Therefore i don't need the step by step solution since i already have it,is just that it doesn't explain why they did it that why.
These are the I1=4A ,I2=1.33, I3=.67, I4=2.67,va=8.0,and vb i don't know.
Please help understanding what is going on in this circuit.
7.jpeg
 
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If you need a loop, put in a 20 V battery with the positive plate connected to E. Connect the negative plate of the battery to the 3 grounds at the bottom of the diagram.
 
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I would work my way up from the bottom, simplifying bits and pieces as I go. R5 and R3 are in parallel, right? So you could combine those two resistors into a single resistance. Keep chipping away at it until you have a single loop.
 
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If you combine circuit elements you will lose that components individual voltage and/or current.

I reccoend doing a KCL at Va and Va. Then solve for Va and Vb, and the currents will be easy to find.
 
thanks for the tip
 
Mark44 said:
I would work my way up from the bottom, simplifying bits and pieces as I go. R5 and R3 are in parallel, right? So you could combine those two resistors into a single resistance. Keep chipping away at it until you have a single loop.
if i do ((R5||R3)+R2)||R4 and this would be in series with R1 right? now to get Vb i think i would do Vb=R5(I2-I3) but what if that R5 was not there then how would i solve for vb
 
Lopez said:
if i do ((R5||R3)+R2)||R4 and this would be in series with R1 right? now to get Vb i think i would do Vb=R5(I2-I3) but what if that R5 was not there then how would i solve for vb
If R5 was not there then I2 and I3 would change. you cannot solve for an unknown value with unknown values
 

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