Engineering AC circuit analysis -- mesh and nodal

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The discussion focuses on solving a circuit analysis problem using mesh and nodal methods. Participants share their equations and solutions for the mesh analysis, with some confusion regarding the signs and components in their calculations. The nodal analysis is also discussed, particularly the concept of supernodes due to fixed potential differences created by voltage sources. Participants are encouraged to verify their equations and ensure proper handling of complex numbers throughout their calculations. Overall, the thread emphasizes collaborative problem-solving and the importance of understanding circuit topology and analysis techniques.
  • #181
There's not much I can do to sort out your arithmetic. But I might suggest that you begin by eliminating the imaginary values from all the denominators of the individual terms and then forming a common denominator (20 looks promising). Since the expression is set equal to zero you can then discard the denominator leaving you with a simpler sum.
 
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  • #182
gneill said:
There's not much I can do to sort out your arithmetic. But I might suggest that you begin by eliminating the imaginary values from all the denominators of the individual terms and then forming a common denominator (20 looks promising). Since the expression is set equal to zero you can then discard the denominator leaving you with a simpler sum.

Its ok I found my mistake hidden amongst bad handwriting. All sorted on a)and b) Thanks for your help.
 
  • #183
Apologies in advance if this isn't in the correct format, I am new to this...

I too have struggled with part b) reading through this thread I have tried to see where I am going wrong, but currently pulling my hair out...

I understand [V20] - [V30] = 14.14+j14.14, (supernode) [EQUATION A]
and also 0 = -[V20]((1/2)+(1/-j5)+(1/j4)+(1/4))+((120/2)+(14.14+j14.14/j4)+(j120/4)+(14.14+j14.14/4))

giving... 0 = -[V][/20]((1/2)+(1/-j5)+(1/j4)+(1/4))+((120/2) + (60+3.535-j3.535+j30+3.535+j3.535)
0 = -[V20]((1/2)+(1/-j5)+(1/j4)+(1/4))+67.07+j30
67.07+j30 = [V20]((1/2)+(1/-j5)+(1/j4)+(1/4))
67.07+j30 = 0.5([V20])+j0.2([V20])-j0.25([V20])+0.25([V20]), [EQUATION B]

However when solving EQUATION A and EQUATION B I seem to get [V20] = 90.1068+j40.3042 and [V30] = 75.9668+j26.1642

then [V20] /[Z4] = (A) = 90.1068+j40.3042/-j5 = -8.06+j18.02 (A)

this is obviously different from the actual answer of -9.152+j17.275 (A) which is what I got for question a.

Can anyone point out where I have gone wrong? thanks.
 
  • #184
Something's gone wrong with your development or solving of EQUATION B. You're okay up to this point:
Ben Yates said:
67.07+j30 = [V20]((1/2)+(1/-j5)+(1/j4)+(1/4))
then you go and distribute V20 across all the terms on the right. Why bother doing that? Reduce the purely numerical part to a single complex value as you did to arrive at the "67.07+j30" term. Then you'll have a simple division left to find V20.
 
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  • #185
gneill said:
Something's gone wrong with your development or solving of EQUATION B. You're okay up to this point:

then you go and distribute V20 across all the terms on the right. Why bother doing that? Reduce the purely numerical part to a single complex value as you did to arrive at the "67.07+j30" term. Then you'll have a simple division left to find V20.

I've now arrived at the correct answer, many thanks!
 
  • #186
hi guys I am stuck at this point:
v1/z1 + v2/z3 - (v20/ z1+z3+z4+z5) + (v3/z5+z3)
can someone help me to proceed please..
 
  • #187
Hi Guys,

Hope it's ok to bump an old thread. I'm working on the same problem and seem to be stuggling to come up with the correct answer for Nodal analysis.

My Analysis thus far:

V30 = V20 - V3

V20 - V1/Z1 + V20/Z4 + V20 - V3/Z5 + (V20 - V3) - V2/Z3 = 0

Expanding:

V20/Z1 - V1/Z1 + V20/Z4 + V20/Z5 - V3/Z5 + V2 - V20 + V3/Z3 = 0

Collecting the V20's and isolating:

V20 (1/Z1 + 1/Z4 + 1/Z5 - 1/Z3) - V1/Z1 - V3/Z5 + V2/Z3 + V3/Z3 = 0

V20 (1/Z1 + 1/Z4 + 1/Z5 - 1/Z3) + V3 (1/Z3 - 1/Z5) + V2/Z3 - V1/Z1 = 0

From this point on I enter the figures into the equations and utilise complex conjugates and/or common denominators to reduce down to a single rectangular complex number.

Am i on the correct path here?
 
  • #188
Joe85 said:
Hi Guys,

Hope it's ok to bump an old thread. I'm working on the same problem and seem to be stuggling to come up with the correct answer for Nodal analysis.

My Analysis thus far:

V30 = V20 - V3

V20 - V1/Z1 + V20/Z4 + V20 - V3/Z5 + (V20 - V3) - V2/Z3 = 0

Expanding:

V20/Z1 - V1/Z1 + V20/Z4 + V20/Z5 - V3/Z5 + V2 - V20 + V3/Z3 = 0

Collecting the V20's and isolating:

V20 (1/Z1 + 1/Z4 + 1/Z5 - 1/Z3) - V1/Z1 - V3/Z5 + V2/Z3 + V3/Z3 = 0

V20 (1/Z1 + 1/Z4 + 1/Z5 - 1/Z3) + V3 (1/Z3 - 1/Z5) + V2/Z3 - V1/Z1 = 0

From this point on I enter the figures into the equations and utilise complex conjugates and/or common denominators to reduce down to a single rectangular complex number.

Am i on the correct path here?
So i think i have figured this out. I took another look at my equations and think i may have been led astray with the (V20 - V3) - V2/Z3

I think it should actually look like this:

V20/Z1 - V1/Z1 + V20/Z4 + V20/Z5 - V3/Z5 + V20 - V2 - V3/Z3 = 0

V20 (1/Z1 + 1/Z4 + 1/Z5 + 1/Z3) - V1/Z1 - V3/Z5 - V3/Z3 - V2/Z3 = 0

From that point i solved using complex conjugates to produce:

V20(0.75 - J.0.05) - (67.071 - J30) = 0

V20(0.75 - J.0.05) = (67.071 + J30)

V20 = (67.071 + J30)/(0.75 - J.0.05)

Converted to both to polar form to divide instead of using a complex conjugate.

73.475∠ 24.098 / 0.752 ∠-3.814

= 87.706 ∠ 27.912

Convert back to Rectangular:

V20 = 86.34 + J45.74

I = V20/Z4
= 86.34 + J45.74/-J5

= -228.7 + J431.7/25

= -9.15 + J17.27A

The same as my answer for MEsh Analysis.

Would greatly appreciate if someone could validate my method or let me know if i have fluked my way to what i think is the correct answer. :)Many thanks,
 
Last edited:

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