Understanding Microscopic Ohm's Law

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SUMMARY

The discussion centers on the microscopic version of Ohm's Law, specifically the equation j = σE, where j represents current density, σ is conductivity, and E is the electric field. Participants clarify that the electric field E is generated within the conductor due to a potential difference from a power source, rather than being solely an external field. The conversation highlights the importance of understanding how current density interacts with electric fields in conductive materials, particularly in the context of transient states and equilibrium.

PREREQUISITES
  • Understanding of electric fields and their properties
  • Familiarity with current density and conductivity concepts
  • Basic knowledge of circuit theory and potential difference
  • Experience with transient analysis in electrical systems
NEXT STEPS
  • Study the derivation and implications of the equation j = σE
  • Explore the concept of electric fields in conductors under varying conditions
  • Learn about transient response in electrical circuits and its mathematical modeling
  • Investigate the relationship between current density and electric field in different materials
USEFUL FOR

Students of physics, electrical engineers, and anyone interested in the fundamental principles of electromagnetism and circuit analysis.

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Homework Statement


Explain the terms used in the microscopic version of Ohm's Law


Homework Equations


j=oE



The Attempt at a Solution


Well I know what we have here is the current density within a conductor is equal to its conductivity multiplied by an 'E-field'. But what is this E-field? Is it an external field that acts upon the wire? But if this is the case will the electrons in the conductor not just move in a few microseconds to go back into equilibrium meaning j=0. You could act on it with an varying field but then how would the calculation work out?
Or is E the field inside the conductor caused by the current density?
Thanks
 
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ed2288 said:

Homework Statement


Explain the terms used in the microscopic version of Ohm's Law


Homework Equations


j=oE

The Attempt at a Solution


Well I know what we have here is the current density within a conductor is equal to its conductivity multiplied by an 'E-field'. But what is this E-field? Is it an external field that acts upon the wire? But if this is the case will the electrons in the conductor not just move in a few microseconds to go back into equilibrium meaning j=0. You could act on it with an varying field but then how would the calculation work out?
Or is E the field inside the conductor caused by the current density?
Thanks

Maybe this helps?
http://hyperphysics.phy-astr.gsu.edu/HBASE/electric/ohmmic.html
 
Hmmm I guess I've spent so long doing electrostatics that I'm struggling a bit with the intuition of currents.
So from the link above, am I right in thinking the E field is from within the wire caused by a potential difference from a power source?
 

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