Understanding Negative Energy in Earth-Satellite Systems

AI Thread Summary
In an Earth-satellite system, the potential energy is defined as -U, while the kinetic energy is expressed as K = -U/2. The mechanical energy is represented as M = -K, but this assertion is challenged within the discussion. It is argued that the satellite is in equilibrium, and any changes in potential energy do not lead to acceleration. The final consensus clarifies that if potential energy is -U, then kinetic energy should be +U/2, resulting in total energy E = -U/2.
ASG141
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the potential energy of a earth-satellite system is -U.

the kinetic energy of the satellite is K = -U/2.

the mechanical energy M = -K.


this is not true.

the satellite is in equilibrium and the ∂θ change caused is limits to zero.

the PE of the satellite cannot cause acceleration in magnitude.
 
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ASG141 said:
the potential energy of a earth-satellite system is -U.
the kinetic energy of the satellite is K = -U/2.
the mechanical energy M = -K.
this is not true.
The last line is true.
If PE=-U, then KE=+U/2, and E=KE+PE=-U/2.
 
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