Understanding Newton's Notation for Derivatives of Velocity and Frequency

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Homework Statement



If velocity = displacement (time)
or
.
x = dx/dt

were you put a dot above the x using Newtons notation were you indicate a derivative with reference to time with a dot above the symbol

so I was like
speed of light = lambda (frequency)
or

lambda with a dot above it = d(lambda)d(frequency)

is this correct because this all the speed of light is? Sense frequency is simply 1/t?

c = lambda frequency
c = lambda/period
lambda (with a dot above it) = d(labmda)d(frequency)

I just never got Newtons notation with the dot thing am I doing this correctly?

Homework Equations


The Attempt at a Solution

 
Last edited:
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The dot is there for the derivative with respect to time only.

So
\dot{f} = \frac{d}{d t} f
 
GreenPrint said:

Homework Statement



If velocity = displacement (time)
velocity is a quotient. The way you have it above, it looks like a product.
GreenPrint said:
or
.
x = dx/dt

were you put a dot above the x using Newtons notation were you indicate a derivative with reference to time with a dot above the symbol

so I was like
speed of light = lambda (frequency)
There's no deriviative involved here. The speed of light, c, is a constant.
GreenPrint said:
or

lambda with a dot above it = d(lambda)d(frequency)

is this correct because this all the speed of light is? Sense frequency is simply 1/t?

c = lambda frequency
c = lambda/period
lambda (with a dot above it) = d(labmda)d(frequency)

I just never got Newtons notation with the dot thing am I doing this correctly?

Homework Equations





The Attempt at a Solution

 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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