In the case of say, radion in the IR spectrum, which causes molecules to vibrate and heat up, what particle is absorbing the photon? Is it just the molecule as a whole?
According to the standard model, any particle with charge can absorb the photon. Typically, however, it will be electrons that do the absorbing of transverse photons.
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R0man
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The particle that absorbs the photon in the case of radion in the IR spectrum is the molecule as a whole. When a photon of a specific frequency is absorbed by a molecule, it causes the electrons in the molecule to become excited and move to higher energy levels. This results in the molecule vibrating at a specific frequency, which in turn causes it to heat up. Therefore, it is the molecule as a whole that absorbs the photon and undergoes the resulting vibrational energy transfer. This phenomenon has important implications in various fields, including chemistry, biology, and materials science. By understanding the causes and implications of photon absorption in molecules, we can better understand and control the behavior of molecules and their interactions with light, leading to advancements in these fields.
I would like to know how to calculate the ##[\hat{H}, \hat{P}]## for a particle in a 1D box? At the first glance it seems that they commute but they don't get diagonalized in identical basis. How to calculate this commutation?
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles.
Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated...
Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/
by @RUTA
I don't know why the electrons in atoms are considered in the orbitals while they could be in sates which are superpositions of these orbitals? If electrons are in the superposition of these orbitals their energy expectation value is also constant, and the atom seems to be stable!