pervect said:
I'd answer a qualified yes to the first question - I would assume you're talking about the 4-version of the magnetic vector potential A if you started talking about 4-potentials in electrostatics, the 4-vector that generates the Faraday tensor when you take it's exterior derivative.
Yes and no. There is a relativistic generalized potential which appears in the Lagrangian. Off the top of my head (and check me on this) this is U = qA*u - q*Phi. The Phi is the Coulomb potential. V = q*Phi is the potential energy of the charged particle in an EM field. The total energy, W, is an integral of motion and has the value
W = K + E_o + V
where V = potential energy.
As far as generalized momentum goes, I'd answer qualified no. Usually a generalized momentum is derived from a Lagrangian, so I'd guess that that's what you were doing, but I don't think I've seen people talk about generalized 4-momenta.
Its well worth your time to check into this. I recommend Goldstein's "Classical Mechanics - 3rd Ed."
I think this is an interesting subject myself. I've been thinking about it more lately and will be making new web pages to describe/discuss it (better than trying to post it all here in Latex

) But I have to wait until my modem comes. Its being shipped by UPS and will be here within a week. I'll be back more then and can get more detailed then too.
One interesting notion is the idea of gauge transformation. E.g. if you take the make the following gauge transformation
A ->
A + grad Psi, then you have to change Phi to Phi -> Phi - @Psi/@t (@ = partial derivative). Psi is a function of space and time. Then the electric field
E = -grad Phi - @
A/@t
becomes
E = -grad (Phi - @Psi/@t) - @(
A + grad Psi)/@t
which simplifies to
E = -grad Phi - @
A/@t
and therefore the field remains unchanged as it must. But if you make this gauge transformation in the Lagrangian then what you're really doing is adding d(Psi)/dt to the original Lagrangian. Since this is the time derivative of a function of space and time it can be deleted from the Lagrangian since both L and L' = L + d(Psi)/dt yield the exact same equations of motion. However the time component of the generalized 4-momentum changes from W to W + @Psi/@t. In such a case the time component of the generalized 4-momentum is no longer the total energy. Interesting stuff.
Happy Thanksgiving by the way!
Pete