Understanding products of triated water decay

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The discussion centers on the decay process of tritium in tritiated water (H2O). When tritium (^3H) decays, it transforms into helium-3 (^3He) and an electron, along with a hydroxide ion (^3HO). There is confusion regarding the charge of the hydroxide, as it appears to require an additional electron, suggesting it is positively charged. The conversation highlights the energetic nature of the decay products, which ionize surrounding water. The complexity of predicting the exact mechanisms of this decay and the subsequent interactions is acknowledged, emphasizing that the system will eventually reach a state of equilibrium despite the various potential pathways involved.
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Figured this was more a chemistry question than nuclear question, so I put it here.

When an atom of tritium in ^{3}_{1}H_{2}O decays, it becomes ^{3}_{2}He^{1+} + e^{-} + ^{3}_{1}HO

This then quickly becomes ^{3}_{2}He + ^{3}_{1}HO

I'm a little confused about the hydroxide. It needs another electron, so it's...positively charged? Anything else I have wrong?
 
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And I just now realized I misspelled "Tritiated" in the title.

Darn.
 
These are rather difficult things to predict. Note that both products of the fission are quite energetic and they both jump away from the initial point, ionizing water around. In the end it will all come to some kind of rest/equilibrium, but exact mechanism can take many paths.
 
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