Understanding Proper Subsets of Ordinals in Searcoid's Theorem 1.4.4 - Peter

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SUMMARY

This discussion centers on the interpretation of Theorem 1.4.4 from Micheal Searcoid's "Elements of Abstract Analysis," specifically regarding the proof involving ordinals. The theorem states that for a totally ordered set, if $$x \subset \alpha$$ and both $$\delta$$ and $$\beta$$ are elements of $$\alpha$$, then the alternatives $$\delta \in \beta$$, $$\delta = \beta$$, or $$\beta \in \delta$$ must hold. The key point raised is the inclusion of the equality condition, which arises when the members are not distinct, thus confirming that equality is a valid alternative in the context of total ordering.

PREREQUISITES
  • Understanding of set theory, particularly ordinals and total orders.
  • Familiarity with the definitions of partially ordered sets and totally ordered sets.
  • Basic knowledge of mathematical proofs and the structure of theorems.
  • Experience with Searcoid's "Elements of Abstract Analysis" or similar texts.
NEXT STEPS
  • Review the definitions of total orders and their implications in set theory.
  • Study the proof techniques used in Theorem 1.4.4 of Searcoid's book.
  • Explore examples of totally ordered sets to solidify understanding of distinct and non-distinct elements.
  • Investigate other theorems related to ordinals and their properties in set theory.
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Mathematicians, students of abstract algebra, and anyone studying set theory who seeks clarity on the properties of ordinals and total orders.

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I am reading Micheal Searcoid's book: "Elements of Abstract Analysis" ... ...

I am currently focused on understanding Chapter 1: Sets ... and in particular Section 1.4 Ordinals ...

I have another question regarding the proof of Theorem 1.4.4 ...

Theorem 1.4.4 reads as follows:
View attachment 8463
In the above proof by Searcoid we read the following:

"... ... Moreover, since $$x \subset \alpha$$, we have $$\delta \in \alpha$$. But $$\beta \in \alpha$$ and $$\alpha$$ is totally ordered, so we must have $$\delta \in \beta$$ or $$\delta = \beta$$ or $$\beta \in \delta$$ ... ... "My question is regarding the three alternatives $$\delta \in \beta$$ or $$\delta = \beta$$ or $$\beta \in \delta$$ ... ...Now ... where $$(S, <)$$ is a partially ordered set ... $$S$$ is said to be totally ordered by $$<$$ if and only if for every pair of distinct members $$x, y \in S$$, either $$x < y$$ or $$y < x$$ ... ..So if we follow the definition exactly in the quote above there are only two alternatives ... $$\delta \in \beta$$ or $$\beta \in \delta$$ ... ...My question is ... where does the $$=$$ alternative come from ... ?

How does the $$=$$ alternative follow from the definition of totally ordered ... ?Help will be appreciated ...

Peter
 

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Peter said:
Now ... where $$(S, <)$$ is a partially ordered set ... $$S$$ is said to be totally ordered by $$<$$ if and only if for every pair of distinct members $$x, y \in S$$, either $$x < y$$ or $$y < x$$ ... ..
Peter

Please, read this definition very very carefully, and ask yourself: what if the pair of members is/are not distinct ?
 
steenis said:
Please, read this definition very very carefully, and ask yourself: what if the pair of members is/are not distinct ?

Thanks Steenis ...

See that key term is "distinct"... if not distinct then members are equal ... enough said ...

Thanks for your help ...

Peter
 

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