Understanding Recoil Kinetic Energy in Atomic Emission: Fact or Fiction?

AI Thread Summary
The formula for recoil kinetic energy after photon emission, Kr = (E1 - E2)^2 / 2Mc^2, is derived from the principles of conservation of energy and momentum. When an electron transitions from energy level E1 to E2, it emits a photon, which carries momentum and energy. The recoil of the atom occurs due to Newton's First Law, where the emitted photon’s momentum results in an equal and opposite momentum change in the atom. The relationship between the photon's energy and momentum (E=cp) is crucial for deriving the kinetic energy of the recoiling atom. Understanding this connection clarifies the validity of the formula and its origins in fundamental physics principles.
MiCasilla
I'm reading in a book that the recoil kinetic energy of an atom after the emission of a photon is:

Kr = (E1 - E2)^2 / 2Mc^2

Where M is the mass of the atom and E1 is the initial level from where the electron jumped back to E2, producing the photon.

Is this true? where does it come from?
 
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Originally posted by MiCasilla
Is this true? where does it come from?
Where does the recoil come from? Newton's First Law. Every action has an equal and opposite reaction.
 
Thank you Russ,

I am not too familiar with this. What I'm trying to find out is where this formula comes from. It is not so obvious to me. In fact I am not even sure if it is right.

When the photon is emitted from the atom I can understand that it recoils, just like a gun does if you shoot...

I assume that the formula came from conservation of energy and momentum, but I do not see how to get there.

Does it make sense to you?
 
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Hello,

If the electron jumps from E1 to E2, the photon has energy (E1-E2), by conservation of energy. A photon's momentum and energy satisfy the relation E=cp (this is probably your missing ingredient). Therefore, the photon has p = (E1-E2)/c. The atom now has momentum -p by conservation of momentum and its kinetic energy is given by Kr = (1/2)M v^2 = (1/(2M)) p^2. Substituting the expression for p from above leads to the answer you seek.

dhris
 
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