Understanding Span and Linear Independence in Vector Spaces

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SUMMARY

The discussion clarifies misconceptions about linear independence and spanning sets in vector spaces. A linearly independent subset does not automatically span the vector space, as demonstrated by a single non-zero vector only spanning in one-dimensional spaces. Conversely, a subset that spans the vector space is not necessarily linearly independent, as the entire vector space cannot be independent. The key concepts are that a maximal linearly independent set spans the space, while a minimal spanning set is linearly independent, both relating to the dimension of the space.

PREREQUISITES
  • Understanding of vector spaces
  • Knowledge of linear independence
  • Familiarity with spanning sets
  • Concept of dimension in linear algebra
NEXT STEPS
  • Study the properties of maximal linearly independent sets
  • Explore minimal spanning sets in vector spaces
  • Learn about the relationship between dimension and basis in linear algebra
  • Investigate examples of linear independence and spanning sets in higher-dimensional spaces
USEFUL FOR

Students of linear algebra, educators teaching vector space concepts, and anyone seeking to deepen their understanding of linear independence and spanning sets.

darkchild
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My professor says that a linearly independent subset of a vector space automatically spans the vector space, and that a subset of a vector space that spans the vector space is automatically linearly independent.

I don't understand why either of these is true.
 
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they aren't. For example, a set containing a single non-zero vector is always independent but only spans in the case of a one-dimensional vector space. The set consisting of the entire vector space, on the other hand, spans the vector space but cannot be independent. You may have misunderstood your professor. A maximal linearly independent set (there is no linearly independent set containing more vectors) spans the space and a minimal spanning set (there is no smaller spanning set) is linearly independent. One can then show that all set that both span the space and are linearly independent contain the same number of vectors (the "dimension" of the space).
 

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