Understanding the Center of Mass in a Hemispherical Bowl in Equilibrium

Click For Summary
SUMMARY

The discussion focuses on the center of mass (c.o.m) of a uniform hemispherical bowl in equilibrium, specifically addressing a scenario where a 2kg mass is placed on the rim of a 3kg bowl. The solution demonstrates that tan(theta) equals 4/3 by analyzing moments about the point of contact with the table. A key point of confusion is the justification for the center of the circular rim being vertically aligned with the point of contact on the horizontal surface. Understanding this alignment is crucial for solving the problem correctly.

PREREQUISITES
  • Understanding of center of mass concepts in physics
  • Knowledge of equilibrium conditions in mechanics
  • Familiarity with trigonometric functions and their applications
  • Ability to analyze moments and forces in static systems
NEXT STEPS
  • Study the principles of static equilibrium in physics
  • Learn about calculating the center of mass for composite bodies
  • Explore the relationship between angles and forces in equilibrium scenarios
  • Review problems involving moments and their applications in mechanics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and equilibrium, as well as educators seeking to clarify concepts related to center of mass and static systems.

Helena54321
Messages
5
Reaction score
0
I know and understand why the c of m of a uniform hemispherical shell (i.e a hollow hemisphere) is r/2 on the axis of symmetry (where r=radius of shell). I looked at the solution of the following question and still don't understand.

Question:

A hemispherical bowl, which may be modeled as a uniform hemispherical shell, has mass 3kg. A mass of of 2kg is placed on the rim and the bowl rests in equilibrium on a smooth horizontal plane. The plane surface of the bowl makes an angle theta with the horizontal. Show that tan theta= 4/3.

Answer: Taking moments about S (the point of contact with the table) :

3g x (r/2)sintheta= 2g x rcostheta.

My problem is I don't understand/know the justification for 0 (the centre of the circular rim of the shell) being on the same vertical line that passes through the point of contact with the horizontal table S.

I first considered the two masses into a composite body and worked out the centre of mass (0.4r, 0.3r) where x-axis is the plane of the circular rim and the y-axis the axis of symmetry of the bowl. This obviously yields the correct answer. But in order to even get this you need to know/understand that 0 is directly above S. Why does this have to be the case?

Can anybody help me? :/ x pweese x

It's in the edexcel M3 book. Exercise 5C Qstn 12. baa humbug
 
Physics news on Phys.org
Helena54321 said:
My problem is I don't understand/know the justification for 0 (the centre of the circular rim of the shell) being on the same vertical line that passes through the point of contact with the horizontal table S.
Would you agree that the table is tangent to the surface of the hemisphere, regardless of where contact is made? And thus a line drawn between the center of the sphere and the point of contact must be perpendicular to table?
 
Man am I stupid. I never get difficult things misunderstood, it's always the easy obvious most important things that I don't see.

THANK YOU! merci! arrigato! xie xie! dou zie! mgoisi!
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 19 ·
Replies
19
Views
4K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 16 ·
Replies
16
Views
5K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K