Understanding the Derivative of F=Fi (sin ct)

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Homework Help Overview

The discussion revolves around differentiating the function F=Fi (sin ct), focusing on the application of the chain rule in calculus.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants present differing solutions to the differentiation problem, with one suggesting a division by c and another asserting the use of the chain rule leading to a multiplication by c. Questions arise regarding the correctness of each approach.

Discussion Status

There is an ongoing exploration of the differentiation process, with some participants providing guidance on the application of the chain rule. Multiple interpretations of the derivative are being discussed, but no consensus has been reached regarding the correct solution.

Contextual Notes

Some participants express confusion over the differentiation process, with one noting that a misunderstanding may stem from mixing differentiation with integration. There are indications of late-night errors affecting the clarity of contributions.

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Homework Statement




differentiate F=Fi (sin ct)




The Attempt at a Solution



Fi is a constant

= Fi (-cos ct)(c)

That is the solution I keep getting, but my buddy keeps getting

Fi (- cost ct)/c

in other words, he thinks - cost ct should be divided by c, anyone care to shed some light?

thanks in advance!
 
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agentnerdo said:

Homework Statement

differentiate F=Fi (sin ct)

The Attempt at a Solution



Fi is a constant

= Fi (-cos ct)(c)

That is the solution I keep getting, but my buddy keeps getting

Fi (- cost ct)/c

in other words, he thinks - cost ct should be divided by c, anyone care to shed some light?

thanks in advance!

Well neither of your solutions are correct. Your solution is the more "correct" of the two.

The derievative of sin(x) is cosx. You should not get a -cos(ct).Your buddy is indeed not differentiating; he is integrating.
 
Should be multiplied with c.

You are using the chain rule (f(g(x))' = f'(g(x))g'(x).
Here f(x) = F_i sin(x) and g(x) = cx.
Using the formula gives F_i cos(cx)*c
 
Last edited:
╔(σ_σ)╝ said:
lol. I think you need to fix your post.



Your final formula is not correct.

Wuups... It is 4:30 AM where I live :( ...
 
Inferior89 said:
Wuups... It is 4:30 AM where I live :( ...

You are completely excused !

I make these errors all the time. Too many times to be honest. :(
 
thanks allot!
 

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