Understanding the Effect of Resistance on Transient Response in RL Circuits

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In RL circuits, increasing resistance shortens the transient response of the inductor due to a reduced ability to store energy. The discharge rate is influenced by the formula [E/R]*e^(-tR/L), indicating that higher resistance leads to a quicker decay of current. In steady state, the inductor acts like a zero-resistance wire, resulting in a final current that is inversely proportional to resistance. Consequently, higher resistance results in lower steady-state current and, therefore, reduced energy stored in the magnetic field of the inductor. Understanding these relationships is crucial for analyzing transient behaviors in RL circuits.
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Can anyone please explain to me why in a RL circuit, using higher values for resistance will shorten the transient response in the inductor? I've read and found a site claiming that it "reduces the amount of energy the inductor can store", can anyone expand on this a little?
 
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The discharge rate is fiven by [E/R]*e-tR/L where E is the e.m.f applied.That should make things clear.
Also in steady state the inductor behaves as a zero-resisitance piece of wire hence it is E/R.At higher values of resistance the current in steady state will reduce and the final energy stored in B field of inductor [which is proportional to i2] will naturally be lesser.
 

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