Understanding the Phase Constant in Simple Harmonic Motion

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The phase constant in simple harmonic motion is determined by the initial conditions of displacement and velocity. For a mass oscillating on a spring with zero initial displacement and negative initial velocity, the phase constant must reflect these conditions. The cosine function starts at a maximum, but since the initial displacement is zero, the relevant point on the curve is where it crosses zero and is moving downward. This indicates that the phase constant should be adjusted to match these criteria. Understanding the relationship between the phase constant and the initial conditions is crucial for solving the problem accurately.
1MileCrash
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Homework Statement



The displacement of a mass oscillating on a spring is given by x(t) = xmcos(ωt + ). If the initial displacement is zero and the initial velocity is in the negative x direction, then the phase constant is:

Homework Equations





The Attempt at a Solution



How do I start? The book just tells me that the phase constant depends on displacement and velocity when t = 0, but doesn't say how.
 
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Sketch a cosine curve. What's its initial value? Where on the curve would match the initial condition of the spring and mass? What's (angular) the offset from zero?
 
gneill said:
Sketch a cosine curve.

OK

What's its initial value?

1

Where on the curve would match the initial condition of the spring and mass?

Huh??
 
Does the mass start at a maximum extension like the cosine function does?
 
No, initial displacement is 0. So, I need to find where cosx equals 0?
 
1MileCrash said:
No, initial displacement is 0. So, I need to find where cosx equals 0?

Not only that, but where it's going through zero and going negative, just like the mass' displacement.
 
Still have no clue on this.
 
Have a gander:

attachment.php?attachmentid=40822&stc=1&d=1320887764.jpg
 

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