Understanding the Properties of Tensor Products: A Demonstration

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SUMMARY

The discussion focuses on the properties of tensor products, specifically demonstrating that the product of an antisymmetric tensor \( A^{rs} \) and a symmetric tensor \( B_{rs} \) results in zero, expressed as \( C^{rs}_{rs} = A^{rs}B_{rs} = 0 \). The participant confirms that interchanging and relabeling indices in the implied double summation is valid, leading to the conclusion that \( 2C^{rs}_{rs} = 0 \). This establishes a fundamental property of tensor algebra regarding the interaction of symmetric and antisymmetric tensors.

PREREQUISITES
  • Understanding of tensor algebra and properties of tensors
  • Familiarity with symmetric and antisymmetric tensors
  • Knowledge of index notation and summation conventions
  • Basic concepts of linear algebra and multilinear mappings
NEXT STEPS
  • Explore the properties of antisymmetric tensors in more depth
  • Learn about symmetric tensors and their applications in physics
  • Study the implications of tensor products in differential geometry
  • Investigate the role of tensors in general relativity and continuum mechanics
USEFUL FOR

Mathematicians, physicists, and students studying advanced topics in linear algebra and tensor analysis will benefit from this discussion.

Telemachus
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I have to demonstrate that if [tex]A^{rs}[/tex] is an antisymmetric tensor, and [tex]B_{rs}[/tex] is a symmetric tensor, then the product:
[tex]A^{rs}B_{rs}=0[/tex]

So I called the product:
[tex]C^{rs}_{rs}=A^{rs}B_{rs}=-A^{sr}B_{sr}=-C^{rs}_{rs}[/tex]
In the las stem I've changed the indexes, because it doesn't matters which is which, but I'm not sure this is fine (because I think r and s could have have associated differents values in the sum).

Then
[tex]2C^{rs}_{rs}=2A^{rs}B_{rs}=0[/tex]
Is this ok?
 
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interchanging and relabeling an implied double summation is okay.
 
Thank you xaos :)
 

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