Understanding the Relationship Between Surface & Line Integrals

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Stokes' theorem connects surface integrals and line integrals by demonstrating that the integral of a vector field over a curve is equivalent to the integral of its curl over a surface. The vector field F has units of u, making the line integral's units u*length. In contrast, the curl of F, represented as ∇×F, has units of u/length, leading to the surface integral having units of u*length when multiplied by the area. This equivalence clarifies how surface area can relate to a line's length in the context of vector fields. Understanding these unit relationships helps clarify the application of Stokes' theorem.
wasi-uz-zaman
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hi experts
as far I know the stokes theorem relates surface integral to line integral - but i am confuse how surface integral if represent area gets equal to length as represented by line integral.
 
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If the vector field F has units u, then the integral of F over a curve has units u*length. Stokes's theorem says that this is the same as the integral of ∇×F over a surface. ∇×F has units of u/length (since each of the partial derivatives does), so the integral of that over a surface has units u/length * length^2 = u*length - just as the integral of F over a curve does. Does that help?
 
great - thanks alot
 

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