Understanding the Shape and Orientation of a Path in Vector Calculus

Click For Summary

Homework Help Overview

The discussion revolves around understanding the shape and orientation of a path defined by the vector function c(t) = (2t, sin(t), cos(t)). Participants are tasked with describing this path between the points (0,0,1) and (π,1,0) in the context of vector calculus.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants explore visualizing the path by projecting it onto different planes, such as the yz-plane, and suggest examining the path in lower dimensions. Questions about the nature of paths and how they relate to functions are raised, along with considerations of how to represent the direction of increasing t.

Discussion Status

There is active engagement among participants, with some offering suggestions to simplify the problem by focusing on 2D representations. Others express confusion about the concept of paths and their implications, indicating a need for further clarification without reaching a consensus.

Contextual Notes

Some participants note the original poster's uncertainty regarding the interpretation of paths and their graphical representation, highlighting a potential gap in understanding the relationship between the path and the function it represents.

calculusisrad
Messages
20
Reaction score
0
Let c(t )=(2t,sint,cost) be a path. Describe the shape and orientation of this path

Describe the shape and orientation between points (0,0,1) and (pi,1,0)

I have no idea how to figure out the shape of a curve from its path and my book is only confusing me. Please help!
 
Physics news on Phys.org
hi calculusisrad! :smile:
calculusisrad said:
Let c(t )=(2t,sint,cost) be a path. Describe the shape and orientation of this path

do the easy bit first …

ignore the x coordinate (ie look at it from the x direction, or project it onto a yz plane) …

what does it look like in 2D ? :wink:
 
I would suggest, perhaps, exploring these functions in fewer dimensions than 3. For example, you are familiar with a plot of two coordinates like so:
x = t
y = f(t)
Plotting the above in an xy plot is the equivalent to y = f(x).

Maybe you're confused, because the graph of the answer does not have "output" versus "independent variable" like you usually have done. Instead, you have output on the x-axis, y-axis, and z-axis. The independent variable is not graphed.

Think to yourself along each axis separately and then fuse the results together in your head. I am assuming your vectors are <x, y, z>. What are the values of x doing as t marches upward? What are the values of y doing as t marches upward? What about the values of z? Can you at least plot an xy slice? Is the yz slice confusing you?

You're not really easy to help since you haven't stated your confusion.

Google complex exponential graph.
 
Thanks you so much for responding! But you guys seems to just be telling me how to graph the function. But its a path, and paths map out the actual function in some weird way I don't understand. Don't I need to take that into account? I'm sorry, I just really don't understand paths at all. I could be completely wrong in my interpretation of the problem.
 
hi calculusisrad! :wink:
calculusisrad said:
… its a path, and paths map out the actual function in some weird way I don't understand. Don't I need to take that into account?

basically, a path is a curve: add an arrow to it to show the direction of increasing t

start with the 2D version in this case …

what does the path look like? :smile:
 

Similar threads

  • · Replies 21 ·
Replies
21
Views
4K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
12
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K