Understanding the Sign Convention for Lens Formula Proofs

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Discussion Overview

The discussion revolves around the use of sign conventions in the derivation and application of the lens formula in ray optics. Participants explore the necessity and implications of applying sign conventions both during the derivation of the lens formula and in subsequent problem-solving scenarios.

Discussion Character

  • Debate/contested
  • Conceptual clarification
  • Mathematical reasoning

Main Points Raised

  • Some participants question the need to apply the sign convention again after it has been used in the derivation of the lens formula.
  • Others argue that the sign convention is essential for maintaining consistency in calculations and determining the position of images relative to the lens.
  • A participant suggests that the formula 1/f = 1/v - 1/u is sign independent during the derivation, but sign conventions become relevant when solving problems.
  • Another participant emphasizes that without a sign convention, it becomes challenging to ascertain whether the image is formed in front of or behind the lens, as well as to differentiate between concave and convex lenses.

Areas of Agreement / Disagreement

Participants express differing views on the necessity of applying sign conventions after the lens formula derivation, indicating that the discussion remains unresolved with multiple competing perspectives.

Contextual Notes

Some participants highlight the importance of sign conventions for clarity in calculations, while others question their necessity, suggesting a potential lack of consensus on the foundational assumptions regarding sign conventions in optics.

Sam Morse
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I googled for lens formula's proof on the internet and found one here

http://www.tutorvista.com/content/physics/physics-ii/light-refraction/convex-lens-formula.php

The problem is that during the course of derivation, it is assumed that image distance is -u following the sign convention. But I don't see why we have to use to sign convention once again while solving problems in ray optics...
 
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Sam Morse said:
I googled for lens formula's proof on the internet and found one here

http://www.tutorvista.com/content/physics/physics-ii/light-refraction/convex-lens-formula.php

The problem is that during the course of derivation, it is assumed that image distance is -u following the sign convention. But I don't see why we have to use to sign convention once again while solving problems in ray optics...

We have chosen the sign convention to maintain consistency while solving the problems.

Direction has been considered...
 
I understand why we use sign convention ... but what's the need of using the sign convention once again ? We have already used the sign convention while deriving the formula for a lens.
 
Sam Morse said:
I understand why we use sign convention ... but what's the need of using the sign convention once again ? We have already used the sign convention while deriving the formula for a lens.

Perhaps, I am of the opinion that while deriving lens formula we use the concept of similar triangles and that formula : 1/f=1/v-1/u is sign independent for now, unless while solving the problems we consider the sign convention.

http://www.tutorvista.com/content/physics/physics-ii/light-refraction/convex-lens-formula.php
 
sankalpmittal said:
Perhaps, I am of the opinion that while deriving lens formula we use the concept of similar triangles and that formula : 1/f=1/v-1/u is sign independent for now, unless while solving the problems we consider the sign convention.

http://www.tutorvista.com/content/physics/physics-ii/light-refraction/convex-lens-formula.php

If you don't use a sign convention the how do you work out whether the image will end up in front of or behind the lens? Also, how do you distinguish between a concave or convex lens? (The answers to those questions are not allowed to include "you specify in words, which side and which type" - the calculation must involve just Maths.)
 

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