Understanding the Step of Integrating $\int u*v'$

[N468989]

Homework Statement

$$\int4x^-3*ln(9x)$$

Homework Equations

$$\int u'*v = u*v - \int u*v'$$

The Attempt at a Solution

i know the answer is $$\frac{-2ln(9x)-1}{x^2}$$

but i don't understand the step $$\int u*v'$$

if any could help me...thanks

 

[mjsd]

what don't you understand

u means u
$$v'$$ means $$dv$$

 

[N468989]

Solved

thks i understand now