Understanding the Step of Integrating $\int u*v'$

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SUMMARY

The discussion centers on the integration of the function \(\int 4x^{-3} \ln(9x) \, dx\) using integration by parts. The key formula utilized is \(\int u'v \, dx = uv - \int u v' \, dx\). The user initially struggled with the step involving \(\int u v'\), which was clarified through community assistance. The final answer derived from the integration process is \(\frac{-2\ln(9x)-1}{x^2}\).

PREREQUISITES
  • Understanding of integration techniques, specifically integration by parts.
  • Familiarity with the notation of derivatives and integrals.
  • Basic knowledge of logarithmic functions and their properties.
  • Ability to manipulate algebraic expressions involving powers and logarithms.
NEXT STEPS
  • Study the integration by parts formula in detail, focusing on its derivation and applications.
  • Practice additional problems involving integration of logarithmic functions.
  • Explore the concept of differentiating logarithmic functions to reinforce understanding of \(v'\).
  • Learn about common integration techniques, such as substitution and partial fractions, for more complex integrals.
USEFUL FOR

Students studying calculus, particularly those focusing on integration techniques, as well as educators looking for examples of integration by parts in action.

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Homework Statement



[tex]\int4x^-3*ln(9x)[/tex]

Homework Equations



[tex]\int u'*v = u*v - \int u*v'[/tex]

The Attempt at a Solution



i know the answer is [tex]\frac{-2ln(9x)-1}{x^2}[/tex]

but i don't understand the step [tex]\int u*v'[/tex]

if any could help me...thanks
 
Physics news on Phys.org
what don't you understand

u means u
[tex]v'[/tex] means [tex]dv[/tex]
 
Solved

thks i understand now
 

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