Understanding the Voltage Across a Broken Lamp

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Homework Help Overview

The discussion revolves around understanding the voltage across a broken lamp in a circuit, specifically questioning why the voltage reading is 12V despite the lamp being broken. The subject area pertains to electrical circuits and voltage division.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand the voltage readings from voltmeters in the circuit, questioning the assumption of infinite resistance for the broken lamp. Other participants explore how voltage would divide in the presence of a small current and varying resistances in the intact bulb.

Discussion Status

The discussion is active, with participants exploring different interpretations of voltage distribution in the circuit. Some guidance has been offered regarding the behavior of voltage across the broken lamp, but no consensus has been reached.

Contextual Notes

There is an assumption that the broken lamp behaves as if it has infinite resistance, and the implications of this assumption on voltage readings are being examined. The presence of a small current and the resistance of the intact bulb are also under consideration.

Icy98
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Homework Statement


Why is the voltage across the broken lamp 12V?

Homework Equations


Can I assume the broken lamp is of infinite resistance?

The Attempt at a Solution


I understand the reading for the first voltmeter is 0V. But can anyone explain to me why the reading of the second voltmeter is 12V?[/B]
 
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That would be a good way to look at it yes. How would the voltages then divide over the two light bulbs if there was a very small current present and the other intact light bulb has a much smaller resistance?
 
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Likes   Reactions: Icy98
Most of the voltage will be across the broken one?
 
Correct.
 
Thank you![emoji3]
 

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