Understanding Torque Direction: A Practical Approach

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The direction of torque is determined using the right-hand rule, where the fingers point along the moment arm and the palm in the direction of the applied force. Torque is perpendicular to both the moment arm and the force, and it indicates the direction of change in angular velocity. In practical applications, torque is often described using "Clockwise" and "Anticlockwise" notation, with Anticlockwise considered positive. This approach helps visualize the effects of torque, such as in the case of a pendulum. Understanding these concepts is crucial for accurately analyzing rotational motion.
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Homework Statement


The direction of a force is the same as the direction of the acceleration this force is creating on a moving object. And the direction of the torque? I am just questioning myself.


Homework Equations





The Attempt at a Solution

 
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\vec{N} = \vec{r} \times \vec{F}

where N is the torque, r = moment arm, F = force

torque is perpendicular to both the moment arm, r, and the force F.
To determine the direction you have to use the right hand rule

your fingers point in the direction of the moment arm and the palm in the direction of the force.
 
Yes, I know that. And the answer to my question is that the torque is in the direction of the change of angular velocity. Thank you, I should have worked a little more before asking.
 
Are you portuguese? I ask that because I see pt on your username. :approve:
 
I would like to add one thing here, in practical applications normally I consider "Clockwise" and "Anticlockwise" notation for torque are more useful. You can imagine a hanging pendulum and if you are forcing it in a way that it tends the pendulum moving in AntiClockWise direction, the torque would be ACW and considered as Positive; for the opposite condition the contrary is applied.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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