Understanding Trans-2-Pentene: A Comprehensive Guide for Confused Individuals

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Trans-2-pentene is a chemical compound with the formula C5H10, characterized by a double bond between the 2nd and 3rd carbon atoms, with trans configuration of methyl and ethyl groups. It serves as a polymerization inhibitor and is used in the production of petroleum resins and amyl alcohols. While its toxicological properties are not fully understood, inhalation of its vapors can irritate the respiratory system, causing symptoms like coughing and shortness of breath. Environmental concerns include its potential toxicity to aquatic life, particularly in lakes, which could harm fish populations. Understanding these aspects is crucial for addressing both health and environmental impacts.
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can someone talk a bit about it cause i am confused about it

thanks
 
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trans-2-pentene is C_5 H_{10}, and has a double bond between the 2nd and 3rd carbons. The methyl and ethyl groups are trans to one another across the double bond. The double bond is also a site of unsaturation.

http://www.neath-porttalbot.gov.uk/images/environment/pollution/species/t2pe.gif for trans-2-pentene :wink:

From http://www.neath-porttalbot.gov.uk/html/environment/pollution/on-line/species/t2pe.html ,

"Trans-2-pentene is a polymerization inhibitor, a solvent and intermediate for the manufacture of petroleum resins and amyl alcohols.

Its toxicological properties have not been thoroughly investigated but vapors are irritating to the respiratory tract. Coughing, laryngitis and shortness of breath may occur at high concentrations. Inhalation may also cause dizziness."

Hope this helps :smile:

devilkidjin said:
can someone talk a bit about it cause i am confused about it
Hmm...any particular feature or problem? More specifically, how does trans-2-pentene trouble you?
 
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ty

um i to be more specific i mean like the environmental? issues to the environement

it might be the lake and the poison to the fish but i am not sure

any help? >.>
 
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TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...

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