Understanding Vector Addition in Physics

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Discussion Overview

The discussion revolves around the topic of vector addition in physics, specifically addressing the correctness of various vector equations and their interpretations. Participants are examining the relationships between vectors \(\vec{r}\), \(\vec{s}\), and \(\vec{t}\) as presented in a problem or key.

Discussion Character

  • Debate/contested

Main Points Raised

  • One participant asserts that the only correct equations are \(\vec{r} = \vec{t} - \vec{s}\) and \(\vec{r} + \vec{s} = \vec{t}\).
  • Another participant challenges the validity of the equations \(\vec{r} + \vec{t} = \vec{s}\) and \(\vec{s} + \vec{t} = \vec{r}\), suggesting they are incorrect unless under unusual conditions.
  • A third participant proposes that the equation \(t - r = s\) is valid.
  • Another participant states that the equations \(t = r + s\), \(r = t - s\), and \(s = t - r\) are equivalent, implying a relationship among the vectors.

Areas of Agreement / Disagreement

Participants express disagreement regarding the correctness of certain vector equations, with no consensus reached on which equations are valid.

Contextual Notes

The discussion includes various interpretations of vector relationships and does not resolve the conditions under which certain equations may hold true.

SweatingBear
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I am stuck on this one:

ZT7emg6.png


According to me, the only correct answers are

[itex]\vec{r} = \vec{t} - \vec{s} \\ \vec{r} + \vec{s} = \vec{t}[/itex]

But according to the key, these are also correct

[itex]\vec{r} + \vec{t} = \vec{s} \\ \vec{s} + \vec{t} = \vec{r}[/itex]

I honestly do not see how, can somebody please explain?
 
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SweatingBear said:
But according to the key, these are also correct

[itex]\vec{r} + \vec{t} = \vec{s} \\ \vec{s} + \vec{t} = \vec{r}[/itex]
Those are wrong, unless you have some special, weird vector spaces.
 
However it does look like t - r = s.
 
That is another valid equation. t=r+s, r=t-s and s=t-r are equivalent.
 
Thanks.
 

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