Understanding Vector Addition in Regular Polygons

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Vectors drawn from the center of a regular n-sided polygon to its vertices sum to zero due to the symmetry of the polygon. When the polygon is rotated about its center, the relative positions of the vertices remain unchanged, maintaining the balance of the vectors. This symmetry implies that for every vector pointing in one direction, there is an equal vector pointing in the opposite direction. Analyzing specific cases, such as a square or hexagon, can clarify this concept. Understanding the rotation by 2π/n reveals that the problem remains unchanged, leading to a straightforward proof that the sum of the vectors is indeed zero.
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Vectors are drawn from the center of a regular n-sided polygon in
the plane to the vertices of the polygon. Show that the sum of the
vectors is zero. (Hint: What happens to the sum if you rotate the
polygon about its center?)

can anybody help me out with this question? and what does the rotation of the polygon have to do with this addition of vectors? I am not able to understand this question at all.
 
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Danish_Khatri said:
Vectors are drawn from the center of a regular n-sided polygon in
the plane to the vertices of the polygon. Show that the sum of the
vectors is zero. (Hint: What happens to the sum if you rotate the
polygon about its center?)

can anybody help me out with this question? and what does the rotation of the polygon have to do with this addition of vectors? I am not able to understand this question at all.

Draw the problem for a 4-sided polygon, and see if it makes sense. Then a 6-sided polygon, etc.
 
Danish_Khatri said:
... what does the rotation of the polygon have to do with this addition of vectors?

The hint is asking you to look at the symmetry of the problem. Actually, it is asking you to do more than just rotate the figure. The expectation is that you will realize that there is something very special about rotating by 2pi/n. When you do so, do you have a different problem, or the same problem? The answer to this question can lead you to a very simple and elegant proof that the sum of the vectors is zero.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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