Understanding Velocity Direction in Basic Physics Equations

Click For Summary

Homework Help Overview

The discussion revolves around understanding the direction of velocity in the context of a physics problem involving a hot-air balloon and a dropped compass. Participants are exploring the implications of positive and negative velocity values in kinematic equations.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are questioning how to determine the sign of velocity in their calculations. There are discussions about the expected negative velocity for falling objects and the interpretation of initial conditions in the problem. Some participants are sharing their attempts to solve similar problems and seeking further guidance on time calculations.

Discussion Status

Some participants have provided insights regarding the expected sign of velocity for falling objects, while others are still seeking clarification on the time it takes for the compass to hit the ground. Multiple interpretations of the problem are being explored, and guidance has been offered regarding the use of kinematic equations.

Contextual Notes

Participants are working with different values in similar scenarios, which may lead to varying interpretations and approaches. There is an emphasis on understanding the implications of initial conditions and the direction of motion in their calculations.

duki
Messages
264
Reaction score
0
Hey all,


I was wondering if someone could explain how to tell whether V = - or +?

I'm getting answers right using the formula

V^2 = sqrt(Vo^2 + 2ay)

but I'm getting positive answers. How do you tell whether the velocity is in the + or - direction?


Sample Question:

A hot-air balloon is rising upward with a constant speed of 2.50m/s. When the balloon is 3.00m above the ground, the balloonist accidentally drops a compass over the side of the balloon. How much time elapses before the compass hits the ground?


I got V = 8.1m/s but the right answer requires using -8.1m/s.

thanks for any help :)
 
Physics news on Phys.org
They expect you to know that a falling object hits the ground with negative (downward) velocity!

Both answers are consistent with the given initial conditions of acceleration and velocity. But only one of those answers is the one you're looking for. The other answer is the velocity the object would have to leave the ground with to end up 3 m high with the given speed. (In other words: What goes up, comes down. :wink: )
 
ah ok. that makes since... thanks!
 
hi,

i saw the thread and wanted to know how we would actually go about answering the questions it asks. I figured out how to solve the problem but I can't figure out how many seconds it would take for the compass to drop. please help.

thanks,

Z
 
deuceszbigz said:
I figured out how to solve the problem but I can't figure out how many seconds it would take for the compass to drop.
What have you figured out so far?
 
i basically have the same example, but the values given to me are different. the problem i have is:

A hot-air balloon is rising upward with a constant speed of 2.20 m/s. When the balloon is 3.50 m above the ground, the balloonist accidentally drops a compass over the side of the balloon. How much time elapses before the compass hits the ground?

i was able to solve as far as the other student, but then I get stuck. any suggestions?
 
The best equation for you to use is

s = s_0 + v_0 t + 1/2 a t^2

Solving for t is then a quadratic. (Why does this topic have so many views?)
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 4 ·
Replies
4
Views
6K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 26 ·
Replies
26
Views
3K
  • · Replies 9 ·
Replies
9
Views
8K
Replies
40
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K