Calculating Time for an Object to Fall in One Dimension

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Homework Help Overview

The problem involves a hot air balloon rising at a constant speed and the subsequent drop of a compass from it. The objective is to determine the time it takes for the compass to hit the ground after being released from the balloon, which is 3.00 m above the ground.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the initial velocity of the compass at the moment of release, with some suggesting it should be 2.50 m/s upward, while others consider the perspective of the balloonist and the ground.

Discussion Status

There is an ongoing exploration of the initial conditions of the problem, particularly regarding the initial velocity of the compass. Multiple interpretations of the scenario are being considered, and participants are providing insights into the physics involved without reaching a consensus.

Contextual Notes

Participants note the importance of sign conventions when applying the kinematic equation, as displacement and acceleration due to gravity are in opposite directions.

ShamTheCandle
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Hi. I am new to Physics Forums. The following problem is from Physics 6th Edition by Cutnell/Johnson.

A hot air balloon is rising upward with a constant speed of 2.50 m/s. When the balloon is 3.00 m above the ground, the balloonist accidentally drops a compass over the side of the balloon. How much time elapses before the compass hits the ground?

I tried to solve this question by using formula below:

h=v_0t+\frac{1}{2}at^2

However, I am not sure what is the value of v_0. Is it zero or 2.50 m/s?

Thanks for taking your time to read. :smile:
 
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Hi

Vo will be 2.5 m/s in the direction the balloon is moving. If it wasn't then if you where in a moving car and you threw a ball it would fly to the back of the car at the speed the car is moving.. and that don't happen :)
 
If the balloonist is holding it in his hand, the instantaneous initial velocity of the compass at the time of release is zero with respect to him. Now the balloonist is moving with respect to the ground, so the initial velocity of the compass with respect to the ground is ...
 
Hi ShamTheCandle,
Welcome to PF.
Before dropping, the compass is moving up with the balloon. So its initial velocity is 2.5 m/s upward. Here displacement and g are in the down ward direction. While substituting in the formula take care about the signs
 
Thanks all! I appreciate your help. :smile:
 

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