BlueCardBird said:
Can anyone briefly explain to me when using conservation of energy to calculate for vertically mounted spring questions, why gravitational potential energy is neglected?
Because the gravity field just changes the height that the hanging mass balances. So gravity's effective action is just to expand the natural length of the spring. Now, because the gravity potential is linear, equal changes in height result in the same change in gravity potential, regardless of the height those changes happen. To clarify the above, take a look at these equations about the equation of motion and the total potential energy in 2 cases: a) in absence of gravity and b) with gravity. We assume that z = 0 is the point where the hanging mass experiences no spring force in the absence of gravity.
a) F = -k z
V = [itex]\frac{1}{2}[/itex] k z
2
b) F = -k z - m g = -k (z+z
0) , where z
0 = mg/k
you see that the mass balances now at z = -z
0 , a little longer than before. So you can study the problem using the new variable ζ = z + z
0 . The equation of motion will be:
F = -k ζ
which is equivalent to a) case.
V = [itex]\frac{1}{2}[/itex] k z
2 + m g z = [itex]\frac{1}{2}[/itex] k (z+z
0)
2 - [itex]\frac{1}{2}[/itex] k z
02
Since constant terms in potential energy have no physical significance, you can drop them and define the equivalent potential function:
V
* = [itex]\frac{1}{2}[/itex] k ζ
2
Compare the equation of motion and the potential function in a) and b) cases, and get your answer!