Understanding Voltage in EM Circuits: A Student's Query

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The discussion centers on the complexities of defining voltage in electromagnetic (EM) circuits, particularly in the context of AC circuits and inductors. The original poster struggles with the path-dependent nature of voltage as defined by the integral of the electric field (E), questioning its validity without a clear convention. Responses clarify that while the line integral of E can depend on the path in time-varying fields, the quasi-static approximation allows for a consistent definition of voltage by treating induced electric fields as conservative. The conversation emphasizes the need for a comprehensive understanding of potential energy and the assumptions underlying voltage definitions in dynamic circuits. Ultimately, the quest for a coherent explanation of voltage in these contexts remains a focal point of the discussion.
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I'm currently taking an EM course. We're doing AC circuits, but I'm having a hard time understanding how voltage is defined.

In the electrostatic context I understand how the voltage is defined as the line integral of E over a path, and I get how that line integral has nice path-independent properties because E has no curl. But then our course introduces magnetism, and circuits. The sort of circuits we're looking at have inductors, or lots of self-inductance, so even magneto-statics goes out the window.

When I ask about how voltage is defined in this more complicated context I get lots of answers like "voltage is still just the integral of E * dl", but I'm not happy with that because it's path-dependent, and therefore meaningless unless a convention is chosen for taking the path (which I've never seen done), or unless an argument is given for why that detail isn't important (which I've also never seen done).

I also sometimes get answers like "voltage is just the difference in potential energy divided by charge," but I'm also not happy with that because people giving this answer uniformly fail to answer the follow-up question of "what is potential energy?" You can't define electric potential energy in usual way, for the reasons I just explained in the last paragraph. And anyway there are some choices of gauge for which the \phi in \vec E = -\nabla\phi - d{\vec A}/dt is declared by fiat to be \phi=0 everywhere and at all times (which has interesting consequences for how \vec A has to be defined, but nonetheless renders the concept of the scalar potential null and void).

Lastly, I get a lot of people saying that I'm overcomplicating things. But all I'm asking is for some definition of this pervasively used concept of "voltage" that doesn't have big gaping holes in it. I don't think that's too much to ask for, and I think it's worth nitpicking about. If there are assumptions or approximations going on that render my nitpicking extraneous, then I want to know exactly what those assumptions or approximations are.

Also, to the admins: I wasn't sure where to post this question. If I'm in the wrong section then feel free to move me.
 
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pmr said:
When I ask about how voltage is defined in this more complicated context I get lots of answers like "voltage is still just the integral of E * dl", but I'm not happy with that because it's path-dependent, and therefore meaningless unless a convention is chosen for taking the path (which I've never seen done), or unless an argument is given for why that detail isn't important (which I've also never seen done).

No, it's not path-dependent. Say you have a coil with some electric field induced in the turns. You may, during integration of the total voltage-difference over the coil, choose a path through the turns and get a result, or you may choose a path that jumps from one turn, through an airgap, to another turn (missing one or more turns). You will get the same result because in the airgap there will be an electric field (induced by the voltage-difference between one turn to the other), and when you integrate through this airgap, you will exactly get a voltage-difference that matches the voltage-difference integrated through the missing turns. So you may choose the path as you like, making loops, jumps, whatever: You will get the same result.

( I don't know if I have understood your confusion correctly here? )
 
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You are right that in AC circuits and generally circuits with time varying current the line integral of E depends on the path because CurlE is not zero, however you do the so called "quasi static" approximation that CurlE=0 , which essentially means that the time varying of E is solely due to a time varying scalar potential \phi.

It should be clear how this approximation works in the case of a capacitor (where the time varying E between its plates is mainly due to the time varying charge accumulation in its plates which creates a time varying scalar potential, that is for frequencies of no more than a few Ghz).

In the case of inductor, the time varying vector potential A and the associated non conservative electric field E_{\vec{A}}=-\frac{d\vec{A}}{dt} initiate the process of creating surface charges in the surface of the wire that the inductor is made, which surface charge result in a conservative electric field E_{\phi}=-\nabla\phi such that the total electric field E_{\phi}+E_{\vec{A}}\approx 0 is almost zero in the region inside the wire of the inductor. So you can take as E just the conservative constituent E_{\phi} and define as V=\int E_{\phi}dr=-\int E_{\vec{A}}dr.
 
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It may be shown from the equations of electromagnetism, by James Clerk Maxwell in the 1860’s, that the speed of light in the vacuum of free space is related to electric permittivity (ϵ) and magnetic permeability (μ) by the equation: c=1/√( μ ϵ ) . This value is a constant for the vacuum of free space and is independent of the motion of the observer. It was this fact, in part, that led Albert Einstein to Special Relativity.
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