Understanding Work Done: A Bicycle Puncture Example

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In a bicycle puncture, the escaping air does work on the surrounding air by pushing it back, illustrating the concept of work done. The air remaining in the tire also performs work as it expands and pushes the escaping air ahead of it. This interaction highlights two instances of work being done during the puncture event. Contrary to initial assumptions, the temperature of the air decreases as it expands. Understanding these dynamics clarifies the mechanics of work in this scenario.
Faiq
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How is in a bicycle puncture, the air flowing out of the puncture constitutes as an example for work done?
 
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Faiq said:
How is in a bicycle puncture, the air flowing out of the puncture constitutes as an example for work done?
Work done on what by what?
 
I also don't know that. The question was stated as "In which example is work done?" and this option is the correct answer
 
Faiq said:
I also don't know that. The question was stated as "In which example is work done?" and this option is the correct answer
Well the escaping air does work on the surrounding air in pushing it back. And the air still remaining in the tire does work on the air that it is pushing out ahead of it. So there are two places where work is being done.
 
How is the still air pushing the escaping air out?
 
Faiq said:
How is the still air pushing the escaping air out?
The air remaining in the tire is expanding as it pushes the air ahead of it out. So it is not still air.
 
Temperature has increased in this example (since the air is expanding)?
 
Faiq said:
Temperature has increased in this example (since the air is expanding)?
Temperature decreases in this example since the air is expanding.
 
Oh yeah sorry got it
 

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