Understanding Work in Falling Bodies: Gravity, Energy, and Convention

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Discussion Overview

The discussion revolves around the concept of work in the context of a body falling under the influence of gravity. Participants explore the definitions and conventions regarding whether the work is done by the force of gravity on the body or by the body itself. The conversation includes calculations and interpretations of work done during the falling and lifting of a body, examining the implications for energy gain and loss.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • Some participants assert that the work done during a fall is positive and is done by gravity on the body, leading to a gain in kinetic energy.
  • Others argue that if work is done by the body, it would imply a loss of energy, creating confusion about the correct interpretation of work in this context.
  • A participant presents calculations using a coordinate system to analyze the work done by gravity and questions why the signs of work do not appear to be opposite in different scenarios.
  • Some participants clarify that the integral calculations reflect work done by gravity, and emphasize that the direction of force relative to displacement determines the sign of the work.
  • There is a discussion about the work-energy theorem and how it applies to the scenarios presented, with some participants correcting earlier claims regarding the nature of the work done.

Areas of Agreement / Disagreement

Participants express differing views on the interpretation of work done by gravity versus work done by the body. While some agree on the positive nature of work done by gravity, others maintain that the distinction between who is doing the work leads to confusion and disagreement remains on the interpretation of signs in the calculations.

Contextual Notes

Participants highlight potential limitations in their calculations, including the dependence on coordinate system definitions and the need for clarity on the roles of forces in determining work done. There is also an acknowledgment of unresolved aspects regarding the signs of work in different scenarios.

mpkannan
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When a body falls from a height (h) under gravity,the work involved is mgh. How do you describe this work? Is it 'work done by the force (gravity) on the body' or 'work done by the body'. The confusion is, if work is done on the body the body gains energy; but if work is done by the body the body loses energy. What is the standard convention?
 
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mpkannan said:
When a body falls from a height (h) under gravity,the work involved is mgh. How do you describe this work? Is it 'work done by the force (gravity) on the body' or 'work done by the body'. The confusion is, if work is done on the body the body gains energy; but if work is done by the body the body loses energy. What is the standard convention?

Not necessarily so. If the work is negative, the body loses energy.
 
mpkannan said:
When a body falls from a height (h) under gravity,the work involved is mgh. How do you describe this work? Is it 'work done by the force (gravity) on the body' or 'work done by the body'. The confusion is, if work is done on the body the body gains energy; but if work is done by the body the body loses energy. What is the standard convention?
Since gravity acts on the body, we're talking about work done on the body, not by the body. That work happens to be positive as the body falls, since the force and the displacement are in the same direction. (If the body were moving upward, the work done by gravity would be negative.)
 
Doc Al said:
Since gravity acts on the body, we're talking about work done on the body, not by the body. That work happens to be positive as the body falls, since the force and the displacement are in the same direction. (If the body were moving upward, the work done by gravity would be negative.)

Pl. see the following calcultions and advise me on the error involved:

(1) I consider a Cart coordinate system (drawn as per the right hand thumb rule) with +ve Z axis pointing upwards. Now, consider a body falling from z=h to z=0. The work involved is:

Integral (from h to 0) of [-mg dz] (-mg, because the force is acting downwards). The answer is mgh. Is this not the work done by the body, since it loses this much energy on fall? If so why it is not negative?

(2) If I raise the body from 0 to h, the work done on the the body is:

Integral (from 0 to h) of [mg dz] (here force applied is equal and opposite to gravity; so +mg). The asnwer is mgh. The body gains this much energy and stores it as its potential energy.

Why I am not getting opposite signs for the 2 types of work involved?
 
(1) This is work done by the gravity on the body, not by the body. The body gains kinetic energy . Work done = gain in KE (this is work energy theorem) The integral is positive , if you have done your integration correctly.
(2) This is the wrong integral , as the gravity is still downward so it should be Integral (from 0 to h) -mg dz, and the integral this time is negative. So there is a loss of kinetic energy.
 
mpkannan said:
(1) I consider a Cart coordinate system (drawn as per the right hand thumb rule) with +ve Z axis pointing upwards. Now, consider a body falling from z=h to z=0. The work involved is:

Integral (from h to 0) of [-mg dz] (-mg, because the force is acting downwards). The answer is mgh. Is this not the work done by the body, since it loses this much energy on fall? If so why it is not negative?
No, it's not the work done by the body. Gravity (-mg) acts on the body.

(2) If I raise the body from 0 to h, the work done on the the body is:

Integral (from 0 to h) of [mg dz] (here force applied is equal and opposite to gravity; so +mg). The asnwer is mgh. The body gains this much energy and stores it as its potential energy.
Good.

Why I am not getting opposite signs for the 2 types of work involved?
Positive work was done in each case. In case 1, gravity did the work; in case 2, you did the work.

In case 2 the work done by gravity (not you) is negative, but you didn't calculate that.
 
My apologies for the (2) as I have not noticed that you are calculating the work done by hand and not work done by gravity.
So yes, the work is integral from 0 to z (mg dz).
In both cases, the work is positive because they share a common thing:
The force is in the same direction as the displacement.
 

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