Uniform acceleration of rolling cart

Click For Summary
SUMMARY

The discussion focuses on a lab experiment involving a rolling cart on a ramp, where a tickertape recorded the cart's motion. Key findings include the creation of distance-time, average velocity-time, and acceleration-time graphs, revealing that the average velocity calculated was lower than the expected gravitational acceleration of 9.8 m/s², yielding a result of 6.5 m/s². The discrepancies between average and instantaneous velocities, as well as the reasons for the average velocity-time graph not passing through zero, were also explored, highlighting the importance of time intervals in measuring velocity accurately.

PREREQUISITES
  • Understanding of kinematics and motion graphs
  • Familiarity with tickertape timing methods
  • Knowledge of calculating average and instantaneous velocity
  • Basic principles of acceleration due to gravity
NEXT STEPS
  • Investigate the effects of time intervals on velocity measurements
  • Learn about the differences between average and instantaneous velocity in physics
  • Explore potential sources of systematic errors in lab experiments
  • Study the principles of graphing motion and interpreting slopes
USEFUL FOR

Students in physics, educators conducting motion experiments, and anyone interested in understanding the principles of kinematics and graphing motion data.

jnimagine
Messages
176
Reaction score
0
We did a lab, where a cart was rolled down a ramp and a tickertape was attached to the cart as it rolled down. When the cart finished the course of rolling down, a line was drawn across the tape through every sixth dot to show that it is an interval of 0.10s.
Then we had to make 3 graphs: distance - time, average velocity - time, and acceleration - time.
When the displacement was graphed, the graph was a curve. The average velocity was calculated by subtracting the displacement at 0.10s from the displacement of 0.20s then dividing it by 0.10s.
When tangents were drawn on the distance time graph and slopes calculated to find out the instantaneous velocity, the slopes were slightly larger than all the average velocities. It said that the average and the instantaneous velocity must be the same. Why is that?? and what could explain the differences between the two in my result?
Also, what are some reasons why the average velocity - time graph does not pass through zero?
When the average velocity was graphed and a line of best fit was drawn, the slope was caculated to figure out the acceleration. This acceleration was only 6.5m/s^2 instead of 9.8m/s^2. What could be some errors in the lab (not human errors) that could have caused this problem??

If anyone could suggest some explanations to my questions, I would greatly appreciate it. Thank you. :)
 
Physics news on Phys.org
Easy question first, why the graph does not pass through zero. it does not pass through zero because you started with a velocity interval between t=0s and t=.1s. The smaller that time interval, the closer you would get to a starting velocity of zero. You could have also held the cart at the top for a few points, then dlet it go. That would get you a line that started at zero then increased.

I do not know offhand why the average and instantaneous velocities would ever be the same in this case. At certain points, with smartly chosen averages you might be able to have them be the same. Also if you took your average speed across a smaller time you would get closer to the instantaneous velocity.
 

Similar threads

  • · Replies 23 ·
Replies
23
Views
3K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 49 ·
2
Replies
49
Views
4K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 19 ·
Replies
19
Views
4K
Replies
1
Views
10K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 124 ·
5
Replies
124
Views
20K
  • · Replies 39 ·
2
Replies
39
Views
5K