Uniform circular motion and coordinate system

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In uniform circular motion, the vertical component of the position vector is greatest at 90 degrees and 270 degrees, where the vector aligns with the y-axis. The vertical component of the particle's velocity is also greatest at these angles, as velocity is tangential to the circle and points in the y direction at these points. The vertical component of acceleration reaches its maximum at 90 degrees and 270 degrees, where it has a purely vertical component. The discussion clarifies that the position vector is indeed a vector, not just a scalar distance. Understanding these components is essential for analyzing circular motion in a coordinate system.
ace123
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2. In the figure below the particle P is in uniform circular motion. The motion is centered on the origin of an xy coordinate system.
(a) At what values of \vartheta is the vertical component r_{y} of the position vector greatest in magnitude?
(b) At what values of \vartheta is the vertical component v_{y} of the particle’s velocity greatest in magnitude?
(c) At what values of \vartheta is the vertical component a_{y} of the particle’s acceleration greatest in magnitude?

a. How can radius have a vertical component? It's just a distance or would it be a displacement?

b. Isn't velocity always tangential to the circle so how would there be a y component? Or does he just mean when it points in the y direction like at zero and 180 degrees?

c. Would it be 90 degrees and 270 because it only has a vertical component?

Any help would be appreciated
 
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The figure is in my gravitational force post. I don't know how to move it. It's question 2.
 
You have the basic idea correct. The magnitude of the y component of each vector is greatest when the whole vector lies along the y-axis. So, your answers to b) and c) are correct.

For part a) you are working with a position vector, not just a distance. The radial position vector points outward from the origin toward the object. Can you answer part a) now?
 
Yea I can answer it now. I just didn't know it was a vector thought it was just a scalar. Shouldn't it just be at 90 degrees and 270 again?
 
ace123 said:
Yea I can answer it now. I just didn't know it was a vector thought it was just a scalar. Shouldn't it just be at 90 degrees and 270 again?

You got it.:smile:
 
Thanks for the help
 
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