Uniform Circular Motion - Finding Fc/Ft without mass

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SUMMARY

The discussion focuses on calculating the tension in a string during uniform circular motion, specifically for a rock swung in a horizontal circle with a radius of 0.95 m and a period of 0.75 s. The user successfully calculates the tangential velocity (V) as 7.9587 m/s using the formula V=(2*pi*r)/t. However, they encounter difficulty in determining the tension (Ft) without knowing the mass (m) of the rock, despite recognizing that mass cancels out in the centripetal force equation (Fc=(mv^2)/r).

PREREQUISITES
  • Understanding of uniform circular motion principles
  • Familiarity with centripetal force and tension concepts
  • Ability to manipulate equations involving velocity and radius
  • Knowledge of basic trigonometry and circular motion equations
NEXT STEPS
  • Study the derivation of centripetal acceleration and its relationship to tension
  • Learn how to apply Newton's second law in circular motion scenarios
  • Explore the concept of mass cancellation in force equations
  • Investigate the effects of varying mass on tension in circular motion
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Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators looking for examples of tension calculations in uniform circular motion scenarios.

Elatric
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Homework Statement


A boy ties a rock to a 0.95 m string and swings it in a horizontal circle directly over his head so that it completes one revolution every 0.75 s. What is the tension in the string?
So we know r and we can calculate V, but that's all I can deduce


Homework Equations


Fc=(mv^2)/r
V=(2*pi*r)/t

The Attempt at a Solution


2*pi*.95/.75= 7.9587 m/s
That's how far I got. I know the masses cancel with ma=mv^2/r but then I end up finding the acceleration. Help?
 
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