Uniform Circular Motion of a motorcycle

AI Thread Summary
A motorcycle traveling at a constant speed of 25.0 m/s over a hill with a radius of curvature of 126 m has a mass of 342 kg. The centripetal force calculated is 1.70 x 10^3 N, which is confirmed correct. However, there was confusion regarding the normal force, initially calculated as 5048 N, but the correct value is 1.66 x 10^3 N. The normal force is determined by the equation Fn = Fg - Fc, where the centripetal force acts towards the center of the curve. The discussion clarifies the relationship between these forces in uniform circular motion.
ShamTheCandle
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Homework Statement


A motorcycle has a constant speed of 25.0 m/s as it passes over the top of a hill whose radius of curvature is 126 m. The mass of the motorcycle and driver is 342 kg. Find the magnitude of (a) the centripetal force and (b) the normal force that acts on the cycle.

Homework Equations



F(centripetal) = mv^2/r
Weight=mg

The Attempt at a Solution


Using the formula for centripetal force, I found that the answer for part (a) is 1.70 x 10^3 N. My answer matches with the back of book. So it is right. However, for part (b) I used that
Normal Force = Weight + Centripetal Force = 5048 N. I don't think it is right since the back of the book says the answer is 1.66 x 10^3.

Thank you for helping.
 
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Last edited:
thefifthlord said:
Centripetal force always acts towards the center, in this case the center is up, so its actually
Edit: Sorry typo.
Fn = Fg - Fc

To anyone who is reading this thread, i need major help here: https://www.physicsforums.com/showthread.php?t=356807

Ohhh, I see. This makes sense now. Thank you!
 
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