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Uniform Circular Motion of a motorcycle

  1. Nov 21, 2009 #1
    1. The problem statement, all variables and given/known data
    A motorcycle has a constant speed of 25.0 m/s as it passes over the top of a hill whose radius of curvature is 126 m. The mass of the motorcycle and driver is 342 kg. Find the magnitude of (a) the centripetal force and (b) the normal force that acts on the cycle.

    2. Relevant equations

    F(centripetal) = mv^2/r
    Weight=mg

    3. The attempt at a solution
    Using the formula for centripetal force, I found that the answer for part (a) is 1.70 x 10^3 N. My answer matches with the back of book. So it is right. However, for part (b) I used that
    Normal Force = Weight + Centripetal Force = 5048 N. I don't think it is right since the back of the book says the answer is 1.66 x 10^3.

    Thank you for helping.
     
  2. jcsd
  3. Nov 21, 2009 #2
    Last edited: Nov 21, 2009
  4. Nov 21, 2009 #3
    Ohhh, I see. This makes sense now. Thank you!
     
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