Uniform circular motion proportionality question

AI Thread Summary
In the discussion about uniform circular motion, the focus is on how the period of rotation changes when the radius is altered while applying the same force. When the radius is doubled, the new period T2 is derived to be T2 = sqrt(2) * T1, indicating that T2 is approximately 1.414 times longer than the original period T1. Conversely, when the radius is halved, the period T2 is found to be T2 = T1 / sqrt(2), making it about 0.707 times shorter than T1. The mathematical approach involves manipulating the formula for the period in relation to the radius and force. This analysis demonstrates a clear relationship between radius and period in uniform circular motion.
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Homework Statement



David spins a sling in a horizontal circle above his head. What would happen to the period of rotation if he applied the same force and the length was a) doubled, b) halved

Homework Equations



ac = (4π2r) / T2

The Attempt at a Solution



Just not sure what to do in general, I tried a few different things like this:

r \alpha T2

2r \alpha T2
r \alpha T2/2

Then compared T2 and T2/2
square rooted both of them

T and T/sqrt(2)

1/sqrt(2) is 0.7, which is the answer to b), even though I was trying to do a).

edit: think I figured it out

I can just equate T and T/sqrt(2) can't I? The first T is Ta, the second is Tb, and that equation is saying that Ta is .7x smaller than Tb, in other words, Tb is 1.4x larger, right?
 
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My approach would be to solve the formula for T:
T1 = 2π*sqrt(mR/F)
I wrote that T1 to indicate it is the original period.
When R is doubled, you get
T2 = 2π*sqrt(m2R/F) and I wish I could make that 2R a red 2 to make it easier to follow. That 2 needs to go out of the sqrt where it becomes a root 2 and move to the front so you can see
T2 = sqrt(2)*2π*sqrt(mR/F) = sqrt(2)*T1
It is an excellent technique; works every time!
 
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