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## Homework Statement

Is (x^2-1) a unit in F[x]? where F is a field.

**2. The attempt at a solution**

I might say yes, cause we can find the taylor expansion of 1/(x^2-1), is my idea right??????

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- Thread starter cummings12332
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- #1

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Is (x^2-1) a unit in F[x]? where F is a field.

I might say yes, cause we can find the taylor expansion of 1/(x^2-1), is my idea right??????

- #2

Dick

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## Homework Statement

Is (x^2-1) a unit in F[x]? where F is a field.

2. The attempt at a solution

I might say yes, cause we can find the taylor expansion of 1/(x^2-1), is my idea right??????

The taylor expansion is not a polynomial. It has an infinite number of terms.

- #3

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A unit is an element that has an inverse. So in order for ##x^2-1## to be a unit, there would have to exist an inverse of ##x^2-1## in your field. Your suggestion of ##\frac{1}{x^2-1}## is a reasonable candidate, but I do not believe it is an element of your field. This is because I always took ##F[x]## to represent the ring of finite degree polynomials over the field, F, and the Taylor expansion of ##\frac{1}{x^2-1}## is infinite.

In my opinion, the answer needs to be "no." I think proving this hinges on the fact that we're in a field (and hence an integral domain) so there is no terms that can multiply by ##x^2## to make the leading coefficient zero.

Good Luck!

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