Finding orthogonal unit vector to a plane

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SUMMARY

The discussion centers on finding a unit vector normal to the plane defined by the equation x − y + √2z = 5 in R3. The initial attempt yielded the vector (1, -1, √2), which was then normalized to (1/2, -1/2, √2/2). However, the correct unit vector is (-1/2, 1/2, -√2/2), which is also valid as it points in the opposite direction. Both vectors are confirmed as unit vectors and perpendicular to the plane.

PREREQUISITES
  • Understanding of vector normalization
  • Familiarity with the equation of a plane in three-dimensional space
  • Knowledge of unit vectors and their properties
  • Basic proficiency in linear algebra concepts
NEXT STEPS
  • Study the process of vector normalization in detail
  • Learn about the geometric interpretation of planes and normal vectors
  • Explore the implications of vector directionality in three-dimensional space
  • Investigate the use of orthogonal vectors in various applications, such as computer graphics
USEFUL FOR

Students studying linear algebra, mathematicians, and anyone interested in vector calculus and its applications in geometry.

Erenjaeger
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Homework Statement



find the vector in R3 that is a unit vector that is normal to the plane with the general equation

x − y + √2z=5

[/B]

Homework Equations

The Attempt at a Solution



so the orthogonal vector, I just took the coefficients of the general equation, giving (1, -1, √2)[/B]
then because it says unit vector i used the fact that v/||v|| gives the unit vector of 'v'
solving for the unit vector (1/2, -1/2, √2/2)
but the correct answer is (-1/2, 1/2, -1,√2)
where have i gone wrong?
 
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Is your vector a unit vector? (amplitude=1). You need to normalize it. It is equally correct if it points in the opposite direction. editing... Reading it closer I see you correctly normalized it. @Ray Vickson also answers it correctly in the post that follows.
 
Erenjaeger said:

Homework Statement



find the vector in R3 that is a unit vector that is normal to the plane with the general equation

x − y + √2z=5

[/B]

Homework Equations

The Attempt at a Solution



so the orthogonal vector, I just took the coefficients of the general equation, giving (1, -1, √2)[/B]
then because it says unit vector i used the fact that v/||v|| gives the unit vector of 'v'
solving for the unit vector (1/2, -1/2, √2/2)
but the correct answer is (-1/2, 1/2, -1,√2)
where have i gone wrong?

Both versions are correct: they are both unit vectors, and both of them are perpendicular to the plane. They just point in opposite directions: one points North and the other points South.
 

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