Unit vectors for multiple particles? (Quantum Mechanics)

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SUMMARY

The discussion focuses on the representation of unit vectors in multi-particle quantum mechanics, specifically regarding the wave function expressed as a tensor product of two spaces, ##|\psi_1,\psi_2>##. Participants clarify that while unit vectors ##\hat{r}_n## define the direction of each particle, they do not form a tensor product when projecting the wave function onto the position basis. Instead, the projection results in an amplitude, represented as a complex number, rather than a tensor product of unit vectors.

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Xyius
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It's been a little bit since I have studied multi-particle quantum mechanics and I am a little rusty on the notation.

Let's say I have a wave function, that consists of the tensor product of two spaces, one for each particle moving, ##|\psi_1,\psi_2>##. Each of these particles is moving in a certain direction defined by their respective unit vectors ##\hat{r}_n##, where ##n=1,2##.

If I were to project this wave function onto the position basis to obtain it's functional form, how would I write the unit vectors? Would the unit vectors also have to be a tensor product? For example,

<\vec{r}_1,\vec{r}_2|\psi_1,\psi_2>=f(\vec{r}_1,\vec{r}_2)\hat{r}_1 \otimes \hat{r}_2

Would this be correct??
 
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No, it's just an amplitude (complex number)
<\vec{r}_1,\vec{r}_2|\psi_1,\psi_2>=f(\vec{r}_1,\vec{r}_2) \in \mathbb{Z}
 
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MisterX said:
No, it's just an amplitude (complex number)
<\vec{r}_1,\vec{r}_2|\psi_1,\psi_2>=f(\vec{r}_1,\vec{r}_2) \in \mathbb{Z}

Oh! Of course! Thanks!
 

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