Universal Gravitation and a satellite

AI Thread Summary
The discussion revolves around calculating the gravitational force exerted by the Earth on a satellite and determining its altitude based on given parameters. The satellite has a mass of 4600 kg and orbits the Earth with a period of 5500 seconds. The user attempts to find the radius of the satellite's orbit using Kepler's equation and gravitational formulas, but initially miscalculates the cube root of R^3. After correcting the misunderstanding, it is emphasized that the correct radius must be derived from accurately taking the cube root of the calculated value. The conversation highlights the importance of careful calculations in gravitational physics.
Bowenj
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Homework Statement


A satellite of mass 4600 kg orbits the Earth (mass = 6.0 1024 kg) and has a period of 5500 s.
(a) Find the magnitude of the Earth's gravitational force on the satellite.
(b) Find the altitude of the satelite


Homework Equations



Kepler's Equation: R^3/T^2

Fg= GmM/R^2

Fc= m4pi^2R/T^2




The Attempt at a Solution



I tried setting Fc= Fg and solving for R. So it ended up being

R^3= GmT^2/(4pi^2)

I plugged the numbers in...

R^3= (6.67e-11)(6e24)(5500)^2/(4pi^2)

so then i solved and took the cube root and got 3.07e20 and plugged that back into the Fg equation so it was

Fg= GmM/R^2

Fg=(6.67e-11)(4600)(6e24)/(3.07e20)^2

which was like... 2.95e-23...? and I'm pretty sure that isn't right...
 
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Fc = m ( omega R)^2 /( R)
Fc= m (2 pi)^2 R / (T^2)
Fg= G M m /R^2

Fc=Fg
R^3 = GM T^2/ (2 pi)^2
no problem
 
Last edited:
Bowenj said:
R^3= GmT^2/(4pi^2)

I plugged the numbers in...

R^3= (6.67e-11)(6e24)(5500)^2/(4pi^2)

so then i solved and took the cube root and got 3.07e20

Those expressions are correct, but 3.07e20 is R3, not R. If you actually take the cube root, you should find the correct answer for the gravitational force.
 
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