Unraveling My Teacher's Math Questions: Explaining the Answers

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These questions are ones that my teacher never explained:

1) if c is a positive integer, then the limit of (1/c)(1/c + 2/c ... + 5c/c) as c approaches infinity can be expressed as

a) integral of x^2 dx from 0 to 1
b) integral of 1/x dx from 0 to 5
c) integral of x dx from -5 to 5
d) integral of x dx from 0 to infinity
e) integral of x dx from 0 to 5

2) the limit as n approaches infinity of (1/n)( (n/1)2 + (n/2)2 + ... + (n/n)2) =

a) the integral of 1/x2 dx from 0 to 1
b) the integral of 1/x dx from 0 to 1
c) the integral of x dx from 0 to 1
d) the integral of x2 dx from 0 to 1
e) none of the above

3) if u is a positive integer, then the limit of (1/u)( (2/u)2 + (4/u)2 + ... + (8u/u)2) can be expressed as

a) the integral of 8/x2 dx from 0 to 1
b) the integral of 1/x2 dx from 0 to 1
c) the integral of 1/x2 dx from 0 to 8
d) the integral of x2/2 dx from 0 to 8

I later found out that the answers were e,a, and d in that order but still need an explanation.
 
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Ok. Now I realize where the start and end points for the integral come from. But not the rest.
 
Anyone?

Also, I think its the limit of the sum of ... whatever expression is there.
 
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Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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