Upward speed of an object in water

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An object with a density of 0.3 gm/cu.cm submerged 10 meters in water will experience buoyancy, causing it to rise to the surface. The upward speed of the object can be calculated by considering its terminal velocity, which is influenced by factors such as shape and orientation. In pure water at 4°C, the density difference creates a significant buoyant force, allowing the object to ascend. The time taken to reach the surface will depend on this terminal velocity. Understanding these dynamics is essential for accurate calculations of the object's upward speed and ascent time.
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If there is an object with a density of 0.3 gm/cu.cm in water, how long will it take to go back up to the surface if it was 10 meters deep in the beginning? Or another question would simply be, what would be the object's upward speed in the water? Is it possible to calculate this?

Assuming it is pure water at 4°C so its density is 1 g/cu.cm

Thanks!
 
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Yoann said:
If there is an object with a density of 0.3 gm/cu.cm in water, how long will it take to go back up to the surface if it was 10 meters deep in the beginning? Or another question would simply be, what would be the object's upward speed in the water? Is it possible to calculate this?

Assuming it is pure water at 4°C so its density is 1 g/cu.cm

Thanks!

Objects traveling in water (usually) quickly attain their terminal velocity under the influence of gravity [when sinking] or buoyancy [when floating to the surface].

Just like for objects passing through the air [another fluid] the shape and orientation of the object will affect that terminal velocity.
 

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