Use L'Hopital's Rule to relate to limit definition for e

Painguy
Messages
118
Reaction score
0

Homework Statement


It can be shown that
lim
n→∞(1 + 1/n)^n = e.
Use this limit to evaluate the limit below.

lim
x→0+ (1 + x)^(1/x)

Homework Equations




The Attempt at a Solution


So i guess what i need to do is try to get that limit in the form of the limit definition for e.

lim
x→0+ (1 + x)^(1/x)

x=1/u

since x-> 0 that means 1/u ->inf

lim
x→0+ (1 + 1/u)^(1/(1/u))

= lim
1/u→∞ (1 + 1/u)^(u) = e

I feel like my last 2 steps are wrong, but I am sure my answer is right.
 
Physics news on Phys.org
Painguy said:

Homework Statement


It can be shown that
lim
n→∞(1 + 1/n)^n = e.
Use this limit to evaluate the limit below.

lim
x→0+ (1 + x)^(1/x)

Homework Equations




The Attempt at a Solution


So i guess what i need to do is try to get that limit in the form of the limit definition for e.

lim
x→0+ (1 + x)^(1/x)

x=1/u

since x-> 0 that means 1/u ->inf

lim
x→0+ (1 + 1/u)^(1/(1/u))

= lim
1/u→∞ (1 + 1/u)^(u) = e

I feel like my last 2 steps are wrong, but I am sure my answer is right.
You have x = 1/u,

so if x → 0+, then so does 1/u → 0+.

What that implies is that u → +∞ .
 
SammyS said:
You have x = 1/u,

so if x → 0+, then so does 1/u → 0+.

What that implies is that u → +∞ .

That makes more sense. Thank you very much.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Back
Top